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steposvetlana [31]
3 years ago
6

Which equation is correctly rewritten to solve for y?

Mathematics
1 answer:
kap26 [50]3 years ago
8 0

Answer : The correct option is, (B) y=\frac{t-d}{31}

Step-by-step explanation :

As we are given that the expression as:

12y+d=-19y+t

By solving the term we get the value of 'y'.

12y+d=-19y+t

We are taking like terms together.

12y+19y=t-d

Now we are adding like terms, we get:

31y=t-d

y=\frac{t-d}{31}

Therefore, the equation correctly rewritten to solve for y is, y=\frac{t-d}{31}

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Solve 2 log x = log 64. (1 point)
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Answer:

8

Step-by-step explanation:

2log(x)=log(64)

By logarithms properties

xlog_{a}(b)=log_{a}(b^{x} )  \\

log(x²)=log(64)

When you have log or ln in both sites, you delete them and...

x²=64

\sqrt[]{x^{2} } =\sqrt{64} \\x=8

7 0
3 years ago
From his home, Clayton would have to walk 4 miles north to get to his friend Miki's house and 1 mile east to get to his friend D
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The houses form a right triangle. Using a²+b²=c² you will find that the distance from Clayton’s house to Danny’s would be 4.1 miles. Adding it all up, the distance would be 9.1 miles of walking.
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Can sum 1 help me plzz
SVEN [57.7K]
A and E is 8 while Q and V are 12. The scale factor will help us find M. 8 goes into 12 1 1/2 times. If you multiply 6 by 1 1/12 you get M. 

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5 0
3 years ago
A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a mediu
yKpoI14uk [10]

Answer:

A) C1 = 0.00187 m = 0.187 cm,  C2 = 0.0062 m = 0.62 cm

B)  A sample of how the graph looks like is attached below ( periodic sine wave )

C) w = \sqrt[4]{3} is when the amplitude of the forced response is maximum

Step-by-step explanation:

Given data :

mass = 5kg

length of spring = 10 cm = 0.1 m

f(t) = 10sin(t) N

viscous force = 2 N

speed of mass = 4 cm/s = 0.04 m/s

initial velocity = 3 cm/s = 0.03 m/s

Formulating initial value problem

y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m

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f(t) = 10sin(t/2) N

using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion

the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)

A) finding the solution of the initial value

attached below is the solution and

B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like

C attached below

3 0
3 years ago
How do i solve (4+6i)+(8-10i)?
ELEN [110]

Answer:

12- 4i

Step-by-step explanation:

(4+6i)+(8-10i)

4+6i+8-10i

4+8+6i-10i

12-4i

6 0
3 years ago
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