Answer:
The total surface area of a regular pyramidis the sum of the areas of its lateralfaces and its base. The general formula for thelateral surface area of a regular pyramidis where p represents the perimeter of thebase and SI the height of inclination.
I belive the answer would be....
49.5-37.5=12
2•12=24
12*123.9=1486.8
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The general form of the geometric sequence is
![a_{n} = a_{1} (r) ^{n-1}](https://tex.z-dn.net/?f=%20a_%7Bn%7D%20%3D%20a_%7B1%7D%20%28r%29%20%5E%7Bn-1%7D%20)
, where a sub n is the number term you're looking for (we're looking for the tenth term). a sub 1 is the first term in the sequence (ours is -6), r is the common ratio, and n-1 is the numbered term you're looking for minus 1. Our formula then looks like this:
![a_{10} =-6(2) ^{10-1}](https://tex.z-dn.net/?f=%20a_%7B10%7D%20%3D-6%282%29%20%5E%7B10-1%7D%20)
. Simplify it to
![a_{10} =-6(2)^9](https://tex.z-dn.net/?f=%20a_%7B10%7D%20%3D-6%282%29%5E9)
. Take 2 to the 9th power then multiply it by -6 to get -3072. C is your answer.
Answer:
97
Step-by-step explanation:
81 + 93 + 76 + 78 + 97 = 425
425/5 = 85