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givi [52]
3 years ago
8

If the old machine is replaced, it can be sold for $32800. Which of the following amounts is a sunk cost? $246000 $820000 $28700

0 $328000

Business
1 answer:
mafiozo [28]3 years ago
7 0

Answer:  $287,000

Explanation:

Sunk costs are costs that have already been incurred and so should make no impact on the decision to be made. In the case of fixed assets to be replaced, the Sunk cost would be the Book value of the Asset.

Sunk Cost of Old Machine = Book Value of old machine

Sunk Cost of Old Machine = Cost Price - Accumulated Depreciation

Sunk Cost of Old Machine = 410,000 - 123,000

Sunk Cost of Old Machine = $287,000

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In the context of international trade, a small country is one that:
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Cant produce much for trade
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4 years ago
The Baldrige Award aims to: (I) publicize successful quality programs. (II) recognize quality achievements of U.S. companies. (I
CaHeK987 [17]

Answer: The Baldrige award aims to publicize successful quality programs, recognize quality achievements of United States companies and stimulate efforts to improve quality. (Option C)

Explanation:

The Malcolm Baldrige National Quality Award is an award that is given to United States organizations in several sectors such as manufacturing, education, services healthcare, business and non profit organizations that have performed exceptionally well. The award recognize companies for excellent performances. It is the only formal recognition of quality performance of private and public organizations that is given by the United States president.

The Baldrige award's goal is to recognize the quality achievements of organizations in the United States, publicize successful quality programs and enhance efforts to improve quality.

3 0
3 years ago
Which of the following is an example of a fixed expense.
emmasim [6.3K]
Raw materials

sales commissions

utilities

<span>property taxes. boom</span>
8 0
4 years ago
$5000 is put into an empty savings account with a nominal interest rate of 5%. No other contributions are made to the account. w
yawa3891 [41]

Answer:

Interest in 5 years will be $1418.07 which is near about $1420

So option (D) will be correct answer

Explanation:

We have given amount invested, that is principal amount P = $5000

Rate of interest r = 5 %

Time taken t = 5 years

As interest is compounded monthly so rate of interest =\frac{5}{12}=0.416%

And time period n = 12×5 = 60 period

So total amount after 5 year will be equal to

A=P(1+\frac{r}{100})^n

A=5000(1+\frac{0.417}{100})^{60}

A=5000\times 1.2836=6418.07

We have to find the interest

Interest will be equal to = total amount - principal amount = $6418.07 - $5000 = $1418.07

Which is near about $1420 so option (D) will be correct answer

 

8 0
3 years ago
On January 1, Year 1, Marino Moving Company paid $48,000 cash to purchase a truck. Marino planned to drive the truck for 100,000
Temka [501]

Answer:

The amount of accumulated depreciation shown on the Year 3=$38,000

Explanation:

Depreciable cost=asset cost-salvage value

where;

asset cost=$48,000

salvage value=$8,000

replacing;

depreciable cost=48,000-8,000=$40,000

The depreciation rate per unit=depreciable cost/planned number of units

where;

depreciable cost=$40,000

planned number of units=100,000 miles

replacing;

depreciation rate per unit=40,000/100,000=$0.4 per mile

depreciation expense for year 1=depreciation rate per unit×actual miles driven

depreciation rate per unit=$0.4

actual miles driven=40,000 miles

replacing;

depreciation expense for year 1=(0.4×40,000)=$16,000

depreciation expense for year 2=depreciation rate per unit×actual miles driven

depreciation rate per unit=$0.4

actual miles driven=20,000 miles

replacing;

depreciation expense for year 2=(0.4×20,000)=$8,000

depreciation expense for year 3=depreciation rate per unit×actual miles driven

depreciation rate per unit=$0.4

actual miles driven=35,000 miles

replacing;

depreciation expense for year 3=(0.4×35,000)=$14,000

depreciation expense for year 4=depreciation rate per unit×actual miles driven

depreciation rate per unit=$0.4

actual miles driven=10,000 miles

replacing;

depreciation expense for year 4=(0.4×10,000)=$4,000

Accumulated depreciation on year 3=depreciation expense for year 1+depreciation expense for year 2+depreciation expense for year 3

accumulated depreciation on year 3=(16,000+8,000+14,000)=$38,000

The amount of accumulated depreciation shown on the Year 3=$38,000

5 0
3 years ago
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