Question

For the reaction, Fe₃O₄ + 4 H₂ → 3 Fe + 4 H₂O, what steps do you have to take to determine how many grams of Fe₃O₄ are required to react completely with 300 grams of H₂?

Answer 1

Answer:

See the steps below (8,681.25 g of $Fe_3O_4$ will be needed0

Explanation:

From the equation, 4 moles of H2 requires  1 mole of Fe3O4.

1st step: calculate the number of mole of 300 g of H2.

mole = mass/molar mass

Mole of 300 g H2 = 300/2 = 150 mole

Hence, 150 moles of H2 will require:  150/4 = 37.5 moles of Fe3O4.

Step 2: Use the mole of Fe3O4 to calculate the mass of Fe3O4

mass = mole x molar mass

mass of 37.5 mole Fe3O4 = 37.5 x 231.5 = 8,681.25 g

Hence, 8,681.25 g of Fe3O4 will be required to completely react with 300 g H2