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3 years ago

If the radius of circle O is 10 inches and m∠UON=90∘, what is the area of sector URN⌢?

Mathematics

1 answer:

arsen [322]3 years ago

6 0

Answer:

75π in²

Step-by-step explanation:

The shaded sector is 3/4 of the circle. We can use the area formula for a circle to find the area of the whole circle, then multiply that result by 3/4.

A = πr² = π(10 in)² = 100π in²

Then the area of 3/4 of the circle is ...

3/4·A = (3/4)·100π in² = 75π in²

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Please answer the question

shusha [124]

The answer should be C. 3

6 0

3 years ago

Please help me understand this problem! I don’t understand the methods to understand how to solve it

Doss [256]

Answer:

Perimeter at the big rectangle is 156 cm.

Step-by-step explanation:

Let's see how to calculate it.

1. First of all you know that perimeter in the blue one is 20cm, so imagine this:

L (long side); S (short side)

2L + 2S =20

and we consider that L = 4S

So, solving the equation:

2.4S + 2S =20

10S=20

S=20/10

S=2

L=8

2. Side at the gold square is 8, the same at the long side in the blue rectangle. So, if you see on the right side in the big one, we got 2 + 8 + 8 + (?). Take a look to the green. Green square is the gold + a short piece and you can understand the short piece as 2 short sides from the blue. If we give numbers we have 8 + 2 + 2, 12.

Now, 2+8+8+12 = 30cm

3. Let's go to the long side in the big one.

We have long side from blue (8) and as you see, side at the orange square must be side at the yellow + short at the blue, so 8+2 =10. We have four oranges square so 10+10+10+10=40, and +8 =48

4. Now that we have the two sides in the big one, let's find the perimeter with the rectangle formula:

2L + 2S =P

2.48 + 2.30 = 156 cm.

7 0

2 years ago

Help me with this question please?

UNO [17]

$\bf 3^{n+2}-3^n=8\cdot 3^n\implies \boxed{3^n\cdot 3^2}-3^n=8\cdot 3^n
\\\\\\
\stackrel{common~factor}{3^n}(3^2-1)=8\cdot 3^n\implies 3^2-1=\cfrac{8\cdot \underline{3^n}}{\underline{3^n}}\implies 3^2-1=8
\\\\\\
9-1=8\implies 8=8$

6 0

2 years ago

Each week Charlene uses 3/4 of a bag of cat food to feed her cats. She has 112 bags of cat food in stock. How long will her stoc

inessss [21]

The stock of cat food will last for 149 weeks.

Step-by-step explanation:

Given,

Bags of cat food in stock = 112

Bags used each week = $\frac{3}{4}\ of\ one\ bag$

Let,

x be the number of weeks.

Therefore,

$\frac{3}{4}x=112$

Multiplying both sides by 4/3

$\frac{4}{3}*\frac{3}{4}x=112*\frac{4}{3}\\x=\frac{448}{3}\\x=149.33$

Rounding off to nearest whole number;

x=149

The stock of cat food will last for 149 weeks.

Keywords: fraction, multiplication

Learn more about fractions at:

#LearnwithBrainly

4 0

3 years ago

(sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^

ArbitrLikvidat [17]

$(sin\theta+sec\theta)^2+(cos\theta+cosec\theta)^2=(1+sec\theta\ cosec\theta)^2\\\\L=sin^2\theta+2sin\theta\cdot\frac{1}{cos\thewta}+\frac{1}{cos^2\theta}+cos^2\theta+2cos\theta\cdot\frac{1}{sin\theta}+\frac{1}{sin^2\theta}\\\\=(sin^2\theta+cos^2\theta)+\frac{2sin\theta}{cos\theta}+\frac{2cos\theta}{sin\theta}+\frac{1}{cos^2\theta}+\frac{1}{sin^2\theta}$

$=1+\frac{2sin^2\theta+2cos^2\theta}{sin\theta\ cos\theta}+\frac{sin^2\theta+cos^2\theta}{sin^2\theta\ cos^2\theta}\\\\=1+\frac{2(sin^2\theta+cos^2\theta)}{sin\theta\ cos\theta}+\frac{1}{sin^2\theta\ cos^2\theta}\\\\=1+\frac{2}{sin\theta\ cos\theta}+\frac{1}{sin^2\theta\ cos^2\theta}\\\\=1^2+2sec\theta\ cosec\theta+sec^2\theta\ cosec^2\theta\\\\=(1+sec\theta\ cosec\theta)^2=R$

4 0

3 years ago