Answer:
A.
Step-by-step explanation:
Answer:
Please see attached image and all steps below for both parts
Step-by-step explanation:
Task 1
The following system of equations includes a linear equation and a quadratic one:

it can be solved by using substitution in the second equation of the variable "y" by the linear expression of the first equation:

and this product of two factors will e zero when either factor is zero, that is: when x = 0, or when x = 9 [to make zero the binomial(x - 9)]
There are two solutions: x = 0 and x = 9.
When we graph both expressions in the system, we see that the line intercepts the parabola at the points (0, 2) and (9, 11). See attached image.
Task 2
Part 1:
Let's pick 30 as a number larger than 25. 30 can be written as 40 - 10
So we can use:

to calculate its square.
Part 2:
let's choose a=9 and b=10 so we use:

Answer:
(7, 3)
Step-by-step explanation:
Answer:
hope that helps
Step-by-step explanation:
3x^2+2xy+y2=2
6x + 2y + 2xy' + 2yy' = 0
x=1 ==> y=-1
6(1) + 2(-1) + 2(1)y' + 2(-1)y' = 0
6 - 2 + 2y' - 2y' = 0
4 = 0
(e) undefined
The graph is an ellipse. At (1,-1) there is a vertical tangent