Answer:
The 32nd term of the arithmetic sequence is -386.
Step-by-step explanation:
Given: The arithmetic sequence where and
We have to find the 32nd term of the arithmetic sequence.
Consider the given sequence with and
We know , For a given sequence in an Arithmetic sequence with first term and common difference d , we have,
We first find the common difference "d".
, we have,
Solve for d , we have,
-88= 8d
d = - 11
Thus, 32nd term is
Thus, The 32nd term of the arithmetic sequence is -386.
A.15 b.500 c.40 d.7.5 yeah, not to confident but I think it's correct.
Answer:
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Step-by-step explanation:
Answer:
Mixed probabilty
Step-by-step explanation:
What is the probability that the first and second ball chosen are both targets, that is, X1 = 1 X2 = 2?
For this we must study the simple probability of each, for example for the target in that event is 5/13. However for the second chosen but also white in the second event where there is already a total of 12 balls is 4/12.
Thus
In this way is generated for all probabilities
b) In the same way analogous to the past example we can perform all cases of combinations, therefore it would be so