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anzhelika [568]
3 years ago
10

In a barangay fiesta singing contest with 12 contestants , in how many ways can the judges choose the first 3 winners

Mathematics
1 answer:
mario62 [17]3 years ago
5 0

Answer: 1320

<u>Step-by-step explanation:</u>

there are 12 choices for 1st place, 11 choices remaining for 2nd place, and 10 remaining choices for 3rd place.

12 x 11 x 10 = 1320

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Okay, let's work this out...
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What we "want to know" :
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That ¦ is 1 way with 16 in 2 rows. Basic multiplication, 16*2=32 or 16+16=32.
But, this is also a way,
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Now there should be 2 in each row and 16 rows. Again 2*16=32 or 2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2=32
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Another way which is 4 rows with 8 in each.
4*8=32 or 8+8+8+8=32
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Now that is 8 rows with 4 in each. 8*4=32 or 4+4+4+4+4+4+4+4=32
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I hope that helped I worked hard typing this all for you. Any questions just ask!
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