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3 years ago

Please, help me in this!! It's very difficult for me. I'm doing assignments in edgeunuity. Please help me in my assignment!!!

Mathematics

1 answer:

marusya05 [52]3 years ago

8 0

Answer:

Inclined plane= 1st option

Wheel and axle= 2nd option

Wedge= 5th option

Pulley= 3rd option

Lever= 4th option

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HELP HELP HELP HELP ME!!!!!!!!!!!!!!!

leonid [27]

Answer:

$l=\frac{A-\frac{1}{2} \pi w^2}{2w}$

Step-by-step explanation:

We essentially need to solve for l; in other words, we must isolate it to one side.

First, notice that the term $\frac{1}{2} \pi w^2$ doesn't have any l terms in it, so we can just move this to the left side by subtracting both sides by $\frac{1}{2} \pi w^2$ :

A - $\frac{1}{2} \pi w^2$ = 2lw

Now, the right side has 2lw, so we must divide both sides by 2w to isolate l:

$l=\frac{A-\frac{1}{2} \pi w^2}{2w}$

~ an aesthetics lover

4 0

2 years ago

If |x| = 2 does X = 2 or x = -2? What is the solution to x = -2?

Effectus [21]

Both solutions are x = 2 and x = -2 are correct

because
when x = 2 , |2| = 2
and
when x = -2, |-2| = 2

hope it helps

7 0

3 years ago

spin [16.1K]

Answer:

$z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67$

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=18 represent the ounce cups of coffee that were underfilled

$\hat p=\frac{18}{100}=0.18$ estimated proportion of ounce cups of coffee that were underfilled

$p_o=0.1$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion it's higher than 0.1 or 10%:

Null hypothesis: $p\leq 0.1$

Alternative hypothesis: $p > 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed for this case is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a one right tailed test the p value would be:

$p_v =P(Z>2.67)=0.0037$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance thetrue proportion is not significanlty higher than 0.1 or 10% .