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Ivanshal [37]
3 years ago
10

Find the circumference of a circle that has a radius of 212 mm

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
4 0

Answer:

1332.035 millimeters

Step-by-step explanation:

If you know the diameter or radius of a circle, you can work out the circumference. To begin with, remember that pi is an irrational number written with the symbol π.  π is roughly equal to 3.14.  You can also work out the circumference of a circle if you know its radius. Remember that the diameter is double the length of the radius. We already know that C = πd. If r is the radius of the circle, then d = 2r. So, C = 2πr.

IceJOKER [234]3 years ago
3 0

Answer:

1332.04

Step-by-step explanation:

C=2πr=2·π·212≈1332.03529

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I hope this helps you



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3 0
3 years ago
One less than the product of four and a number is 11. What is that number ?
agasfer [191]
<h3>One less than the product of four and a number is 11. What is that number ?</h3>

Answer: The number is 3

Step-by-step explanation:

We will call X the number, then 4X - 1 = 11

4X = 11 + 1 =12

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5 0
3 years ago
The top two most profitable Fortune 500 companies in 2016 were Apple and JP Morgan Chase &amp; Co. JP Morgan Chase &amp; Co.'s r
svetlana [45]

Answer:

a. 53.4

b. 24.4

Step-by-step explanation:

a+j=77.8

j=a-29

a+j=77.8

-a+j=-29

2j=48.8

j=24.4

a+24.4=78.8

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5 0
2 years ago
The box plots show the data distributions for the number of customers who used a coupon each hour during a two-day
algol13

Answer:

The correct answer is A: Interquartile range

Step-by-step explanation:

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3 0
3 years ago
A tire company finds that the lifespan for one brand of its tires is normally distributed with a mean of 47,500 miles and a stan
Illusion [34]

Answer:

42580 miles

Step-by-step explanation:

Mean = \mu = 47500

\sigma = 3000

The manufacturer does not want to replace more than 5% of the tires

P(X\leq x)=5\%

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By using normal table values :

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x=(-1.64 \times 3000)+47500

x=42580

Hence the approximate number of miles for the warranty is 42580 miles

6 0
3 years ago
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