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Bond [772]
3 years ago
7

The graph translated horizontally two units right, vertically four units down and reflected across x-axis from its parent functi

on f(x) = x^2. What is the new equation?
Mathematics
1 answer:
Keith_Richards [23]3 years ago
3 0

Parent Function:              f(x) = x^2

Right 2 units:                    f(x) = (x^2 - 2)

Down 4 units:                   f(x) = (x^2 - 2) - 4

Reflection over x-axis:     f(x) = - (x^2 -2) + 4

Answer:                            f(x) = - (x^2 -2) + 4

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Help please!!!! ASAP WILL MARK BRAINLIST IF REALLY FAST
Setler79 [48]

Answer:

1. Product

2. Difference

3. Difference

Step-by-step explanation:

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7 0
2 years ago
Find (r-s) (t-s) + (s-r) (s-t) for all numbers r, s, and t. (a) 0 (b) 2 (c) 2rt (d) 2(s-r) (t-s) (e) 2(r-s) (t-s)
lyudmila [28]
Notice that the 2 expressions have 2 common terms.

(r-s) is just (s-r) times (-1)

similarly

(t-s) is just (s-t) times (-1)

this means that :

(r-s) (t-s) + (s-r) (s-t)=-(s-r)[-(s-t)]+(s-r) (s-t)

the 2 minuses in the first multiplication cancel each other so we have:

-(s-r)[-(s-t)]+(s-r) (s-t)=(s-r) (s-t)+(s-r) (s-t)=2(s-r) (s-t)

Answer:

d)<span>2(s-r) (t-s) </span>
3 0
3 years ago
Read 2 more answers
A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
Chose the step below that correctly uses the distributive property to begin solving the equation:
denpristay [2]
The answer to your question is D
7 0
1 year ago
What is the value of x, when -25(x - 4) = -55(x - 10)?
Finger [1]

-25(x - 4) = -55(x - 10)\\\\-25x+100=-55x+550\ \ \ |-100\\\\-25x=-55x+450\ \ \ \ |+55x\\\\30x=450\ \ \ |:30\\\\x=15

Answer: D) x = 15

3 0
3 years ago
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