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san4es73 [151]
3 years ago
10

The square of the binomial x-4 has the form x^2-ax+16. What is the value of a?

Mathematics
2 answers:
aniked [119]3 years ago
8 0
I think its 8 but i may be wrong but it would look like x^2-8x+16
tia_tia [17]3 years ago
7 0
A=-8x
^^^^^^^^^^^^^^^
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Help!<br>What is the answer to this question?<br><br>​
Nadya [2.5K]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
What is the slope of these two points (2,-6) and (5,-12
Blizzard [7]

Step-by-step explanation:

slope= <u>y</u><u>²</u><u>-</u><u>y</u><u>¹</u>

x²-x¹

<u>-12--6</u>

5-2

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6 0
3 years ago
Let y = safe load in pounds and x = length in feet of a horizontal beam. A constant of proportionality k exists such that y=k/x
Contact [7]

Answer:

Option c. 30,000

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form y*x=k or y=k/x

Let

y ----> safe load in pounds

x ----> length in feet of a horizontal beam

we have

For x=15\ feet, y=2,000\ pounds

Remember that

k=y*x

substitute

k=2,000*15=30,000

7 0
3 years ago
PLEASE ANSWER ASAP CAUSE THIS QUIZ IS DUE SOON
AlladinOne [14]

Answer:

4x-2y=2

Step-by-step explanation:

Line R is represented by the following equation:

x+y=2

We need to choose another system of equation of x+y=2

whose solution is (1,1)

The equation must be satisfy the point (1,1)

Option 1: 2x+y = 2

Put x=1 and y=1

2(1)+1 = 3

3 ≠ 2

False

Option 2: 4x-2y=2

Put x=1 and y=1

4(1) - 2(1) = 2

2 = 2

True

Option 3: 2x-2y=2

Put x=1 and y=1

2(1) - 2(1) = 0

0 ≠ 2

False

Option 4: x+y=4

Put x=1 and y=1

1+1 = 2

2 ≠ 4

False

Hence, The system of equation is 4x-2y=2

5 0
3 years ago
Chose parameters h and k such that the system has a) a unique solution, b) many solutions, and c) no solution. 31+3x2= 4 2x1+kx2
Snezhnost [94]

Answer

a) k=7, h=9, the unique solution of the system is  (x_1,x_2)=(1,1)

b) If k=6 and h=8 the system has infinite solutions.

c)If k=6 and h=9 the system has no solutions.

Step-by-step explanation:

I am assuming that the system is x1+3x2=4; 2x1+kx2=h

The augmented matrix of the system is \left[\begin{array}{ccc}1&3&4\\2&k&h\end{array}\right]. If two times the row 1 is subtracted to row 2 we get the following matrix\left[\begin{array}{ccc}1&3&4\\0&k-6&h-8\end{array}\right].

Then

a) If k=7 and h=9, the unique solution of the system is x_2=\frac{9-8}{7-6}=\frac{1}{1}=1 and solviong for x_1,

x_1+3x_2=4\\\\x_1=4-3(1)=1

Then the solution is (x_1,x_2)=(1,1)

b) If k=6 and h=8 the system has infinite solutions because the echelon form of the matrix has a free variable.

c)If k=6 and h=9 the system has no solutions because the last equation of the system of the echelon form of the matrix is 0x_2=1

8 0
3 years ago
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