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3 years ago

11

Can someone please help me, I don't get worded questions.

1 answer:

serg [7]3 years ago

7 0

I totally understand how they can be frustrating. Try drawing it out as a picture. Draw a straight horizontal line to show where surface of the pool is at. This line is considered to be at 0 meters. Since the swimmer is measured to be 2.3 meters tall with their arms stretched up, and the diving board they are on is 10 meters high, their maximum height is 10m+2.3m which is 12.3m. The depth of the pool, since the surface of the pool is 0m, would be -5.5m (don't forget to always include the unit of measurement, whether it's feet, meters, inches!). Since the diver goes from 12.3m to -5.5m, I would find how far they traveled by writing -5.5m-12.3m=-17.8m; that is, the driver traveled down 17.8 meters.

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To find the distance around the circle?

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Distance around the circle is perimeter.

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Step-by-step explanation:

π = constant =3.14

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Find the dimensions of the rectangle with area 256 square inches that has minimum perimeter, and then find the minimum perimeter

mezya [45]

Answer:

Dimensions: $A=a\cdot b=256$

Perimiter: $P=2a+2b$

Minimum perimeter: [16,16]

Step-by-step explanation:

This is a problem of optimization with constraints.

We can define the rectangle with two sides of size "a" and two sides of size "b".

The area of the rectangle can be defined then as:

$A=a\cdot b=256$

This is the constraint.

To simplify and as we have only one constraint and two variables, we can express a in function of b as:

$b=\frac{256}{a}$

The function we want to optimize is the diameter.

We can express the diameter as:

$P=2a+2b=2a+2*\frac{256}{a}$

To optimize we can derive the function and equal to zero.

$dP/da=2+2\cdot (-1)\cdot\frac{256}{a^2}=0\\\\\frac{512}{a^2}=2\\\\a=\sqrt{512/2}= \sqrt {256} =16\\\\b=256/a=256/16=16$

The minimum perimiter happens when both sides are of size 16 (a square).

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3 years ago