Answer:
$50
Step-by-step explanation:
15x18=270
1170-270=900
900/18=50
The answer is x=6 and y=4.
6+4=10
and 8 times 6 + 12 times 4 is 96.
Answer:
the excel that would be used to construct a confident interval estimate is (A) NORM.S.INV
Step-by-step explanation:
NORM>S>INV returns the of the standard normal cumulative distribution.
Answer:
<em>A special right triangle is a right triangle with some regular feature that makes calculations on the triangle easier, or for which simple formulas exist. For example, a right triangle may have angles that form simple relationships, such as 45°–45°–90°. This is called an "angle-based" right triangle.</em>
Step-by-step explanation:
Hope this helps
Have a nice day :)
Answer:
The answer is below
Step-by-step explanation:
We need to prove that:
(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.
Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.
Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A
