Answer:
The surface area of the given pyramid is 112
.
Step-by-step explanation:
Base length of the pyramid = 4 inches
Area of the base = 
= 
= 16
Area of its base = 16 
Area of one of its triangular surface =
x base x height
=
x 4 x 12
= 2 x 12
= 24 
Area of all its four triangular surfaces = 4 x 24
= 96 
surface area of the pyramid = sum of areas of all its surfaces
= 16 + 96
= 112 
The surface area of the given pyramid is 112
.
91 IS THE AREAS OF THE SIX RECTANGLES
The z-score is given by:
z=(x-μ)/σ
but
x-μ=52
thus
z=52/√84681
z=0.1787
Thus:
P(X≤52)=0.9633
Answer:
h(2) = 7/4
h(-3) = -2
h(-2) = 11/(-8)
h(-3) - h(-2) = -(5/8)
Step-by-step explanation:
h(x) = (2x^2-x+1) / (3x-2)
h(2) = (2*2^2 - 2 + 1) / (3*2 - 2)
= (8 - 2 + 1) / (6 - 2)
= 7/4
h(-3) = {2*(-3)^2 - (-3) + 1} / {3*(-3) - 2}
= (18 + 3 + 1) / (-9 - 2)
= 22/(-11)
= -2
h(-2) = {2*(-2)^2 - (-2) + 1} / {3*(-2) - 2}
= (8 + 2 + 1) / (-6 - 2)
= 11/(-8)
h(-3) - h(-2) = (-2) - {11/(-8)}
= -(5/8)
Hope this will help. Please give me brainliest.
I'm not sure what this question means exactly, maybe the principals goal is unrealistic?