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2 years ago

15

all of the students at mountain range foreign language. 5/8 students take spanish.3/10 of the students take french.the remaining

students take mandarin. what fraction of the students take mandarin?

1 answer:

gladu [14]2 years ago

8 0

Fraction of students taking mandarin: 3/40

Hope it helps.

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Choose all of the transformations that would change a triangle into one that is similar, but not congruent. Which transformation

Vsevolod [243]

You didn't supply a list. The so-called rigid transformations of translation, rotation and reflection create congruent triangles.

Generally it's dilation by a factor about a point is preserves similarity but not congruency. Any transformation which includes such scalings but is otherwise rigid also preserves similarity but not congruency.

8 0

3 years ago

If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=

Alexxx [7]

$\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
\\\\\\
\textit{now, the "y" in the inverse, is really just g(x)}
\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\$

$\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}$

now, if we just knew what g(2) is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that means if we use that value in f(x), f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus 2 = 2x+sin(x)

$\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}$

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it

5 0

2 years ago

Use the tests for divisibility to determine which numbers divide evenly into the given number.

drek231 [11]

The numbers that can divide 648 evenly, using the divisibility tests, include <u>1, 2, 3, 4, 6, 8, 9, 12, and 18</u> and some multiples of any two numbers.

<h3>What is the divisibility test?</h3>

A divisibility test is performed to identify whether a number can be divided evenly by a fixed divisor without a remainder and without actually performing the division process.

<u>Divisibility by 1</u>: Every number is divisible by 1 = 648 (648/1).

<u>Divisibility by 2</u>: 648 is an even number and divisible by 2 = 324.

<u>Divisibility by 3</u>: Sum the digits (18). 18 is divisible by 3 = 6 (18/3).

<u>Divisibility by 4</u>: The last two digits (4 and 8) form a number (12) that is divisible by 4

<u>Divisibility by 6</u>: It is divisible by 2 and by 3

<u>Divisibility by 8</u>: If the hundreds digit is even, the number formed by the last two digits must be divisible by 8.

<u>Divisibility by 9</u>: Sum the digits (18). 18 is divisible by 9

<u>Divisibility by 12</u>: 648 is divisible by 3 and by 4.

<u>Divisibility by 18</u>: 648 is divisible by 2 and by 9.

Learn more about the divisibility tests at brainly.com/question/24125354

#SPJ1

5 0

1 year ago

Please help! I attached the question below.

kompoz [17]

Answer:

$\frac{2(c+2)}{c(c-2)}$

Step-by-step explanation:

$\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }$

Identity used:

$a^{2}-b^{2}=(a-b)(a+b)$

$\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }$

Now let us divide the modified expressions:

$\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})}$ ÷ $\frac{(c-2)^2}{2(6c^{3}+15c^{2}) }$

we get:

$\frac{2(c+2)}{c(c-2)}$

5 0

3 years ago

Ashley is keeping track of the growth of a bamboo plant. When she purchased the plant last month its height was 8.75 inches. Its

Margarita [4]

Answer:

Step-by-step explanation:

Amount by which the plant gre in one month = 9.5 - 8.75 = 0.75

Amount by which it will grow in x months = x * 0.75

The hegiht of the plant after 6 months = amount it will grow by in 6 months + current heigt = 0.75x + 8.75

Hence answer is

d

7 0

3 years ago