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TEA [102]
3 years ago
14

Charlene is knitting a baby blanket. She wants its width, w, to be at least half its length, l. She estimates that she has enoug

h yarn to put fringe around the blanket, as long as the perimeter of the blanket is no more than 180 inches. The system of inequalities shown represents the width of the blanket in inches, w, and the length in inches, l.
w ≥ 0.5l

2l + 2w ≤ 180
Mathematics
2 answers:
Nady [450]3 years ago
7 0

Answer:

60

Step-by-step explanation:

just did it

scoray [572]3 years ago
5 0
W <u>></u> 0.5L

Perimeter:
2L + 2W <u><</u> 180
2L + 2(0.5L) <u><</u> 180
2L + 1L <u><</u> 180
3L <u><</u> 180
<u>÷3       ÷3</u>
  L <u><</u> 60

Length should be less than or equal to 60 inches while width should be greater than or equal to 30 inches.
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You manage a call center that processes orders. One measure of efficiency in your department is the time spent on each call. You
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Answer:

The answer is option A.

Step-by-step explanation:

If the report is made once a month, the daily variations (including the tendency to decrease efficiency on Friday) will be masked within the monthly result.

It would only generate an ethical problem in the case that Fridays fall in different samples, but in the case of the monthly report there are usually 4 or 5 Fridays included in each sample.

4 0
3 years ago
A cab driver charges a fixed rate of $3 plus an additional $1.50 for each mile driven. When representing this situation with a f
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3 0
2 years ago
1. What number comes next in this sequence?
Romashka [77]
The correct answer is B. 592

Explain

The common pattern Number is

48 - 11 = 37 + 22 = 59 - 33 = 26 + 22 = 48 - 11 = 37

37 + 22 = 59
Add 22

59 - 33 = 26

subtract 33

4 0
3 years ago
Help help I’ll give u a thank u if u get it right
madreJ [45]

Answer:

Step-by-step explanation:

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8 0
3 years ago
In △ABC, point D∈ AC with AD:DC=4:3, point E∈ BC so that BE:EC=1:5. If ACDE=5 in2, find ABDC, AABD, and AABC.
Kaylis [27]

Answer:

ar ΔBDC=6 in^2

ar ΔABD=8 in^2

ar ΔABC=14 in^2

Explanation:

Please take a look of attach figure.

We are given area of triangle ar ΔCDE=5 in^2

ar ΔCDE=\frac{1}{2}\times DN\times EC------------(1)

ar ΔBDE=\frac{1}{2}\times DN\times BE------------(2)

Divide eq(2) by eq(1) and we get,

\frac{ar\ ΔBDE}{ar\ ΔCDE}=\frac{BE}{EC}

\frac{ar\ ΔBDE}{5}=\frac{1}{5}

So, ar ΔBDE=1 in^2

ar ΔBDC=ar ΔBDE+ ar ΔCDE

ar ΔBDC=1+5 = 6 in^2

Similarly,

\frac{ar\ ΔABD}{ar\ ΔBDC}=\frac{AD}{DC}

\frac{ar\ ΔABD}{6}=\frac{4}{3}

ar ΔABD=8 in^2

ar ΔABC=ar ΔABD + ar ΔBDC

ar ΔABC=8+6 = 14 in^2

6 0
3 years ago
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