Answer:
Step-by-step explanation:
The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.
1 
= 1
1 1 
1 2 1 
By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is
1 9 36 84 126 126 84 36 9 1
Now, fill in AB in the gaps.
1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB
Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is
Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B
The last step is just to simplify the A^0=1 and B^0 =1 at the first and the last terms.
Hope you can learn the method
Explanation: Just like any of your two-step equations,
in this inequality, start by isolating the x term which in this
case is -3x by subtracting 5 from both sides.
That leaves you with -3x < -24.
To get x by itself, divide both sides by -3 but watch out.
When you multiply or divide both sides of an inequality by a
negative number, you must switch the direction of the inequality sign.
So we have x < 8 and put your final answer in
set notation and it look like this → {x: x < 8}.
Answer:
the answer is $50 for the full price of the sweater
Step-by-step explanation:
if you know $20 is 40% what is 20% it is $10 and then multiple it by 5 because 20 times 5 is 100 and you get 50
The answer is £287.98 is the correct answer
Hello! For this question, you solve using order of operations, which you probably already have remembered as PEMDAS. Anytime a number is raised to the 0 power, that is equivalent to 1. 0.5^0 is 1. 250 * 1 is 250. x = 0 gives us the answer of 250. Now, let's solve for the number by the second power. 0.5² is 0.25. 250 * 0.25 is 62.5. x² gives us 62.5. Now, let's subtract the two numbers together. 250 - 62.5 is 187.5. Because the number is decreasing, the slope is negative, so the answer is -187.5. Your answer is correct.
