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3 years ago

What does x+x+x+x+x-1+1+1+1= ? (Giving this for 30 points)

Mathematics

2 answers:

77julia77 [94]3 years ago

7 0

First, let's add all the x's.

x + x + x + x + x = 5x

5x - 1 + 1 + 1 + 1

Now, let's add together all the 1's that are being added (not the 1 that is being subtracted from 5x).

1 + 1 + 1 = 3

5x - 1 + 3

3 - 1 = 2

5x + 2

There's no way you can actually solve this unless you know the value of x; without x's value, this is as simplified as the expression is going to get.

Hope this helps!

EleoNora [17]3 years ago

4 0

Answer:

im not sure why im awsering this

Step-by-step explanation:

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Answer:

$F(t,y)=(2+7e^t)y+3(1-t)e^t +C$

Step-by-step explanation:

You have the following differential equation:

$e^t(7y-3t)dt+(2+7e^t)dy=0$

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Then, you evaluate the partial derivatives:

$\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}$

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

$F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)$ (1)

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$\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)$

however, the last derivative must be equal to M. From there you can calculate g(t):

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$F(t,y)=(2+7e^t)y+3(1-t)e^t +C$

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Answer:

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ivolga24 [154]

12) (shaded region) 12x25 =300
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