Answer:(2/3) + (9/10) = 47/30
= 1 17/30
Step-by-step explanation:
The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
I'm kind of thrown off for that negative sign, but I try it out in the one that makes sense is this one [ https://gyazo.com/192a76e70d2d46979691cabbf06e6c85 ] If you can better of explain where the negative sign will be great. Hope I helped.
<span>The nonpermissible replacement for the variable x in this expression is x = 2
Substituting x = 2 yields:
(2)^2/(2(2)-4)
4/0, which is undefined.
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