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PSYCHO15rus [73]
3 years ago
9

What percent of 400 is 20?

Mathematics
2 answers:
Phantasy [73]3 years ago
6 0

Answer:

5 %

Step-by-step explanation:

Vinil7 [7]3 years ago
4 0
Answer: 5%

Explanation 1:

20:400*100 =
(20*100):400 =
2000:400 = 5


Explanation 2:

Step 1: We make the assumption that 400 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$x​.

Step 3: From step 1, it follows that $100\%=400$100%=400​.

Step 4: In the same vein, $x\%=20$x%=20​.

Step 5: This gives us a pair of simple equations:

$100\%=400(1)$100%=400(1)​.

$x\%=20(2)$x%=20(2)​.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{400}{20}$
100%
x%​=
400
20​​

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{20}{400}$
x%
100%​=
20
400​​

$\Rightarrow x=5\%$⇒x=5%​

Therefore, $20$20​ is $5\%$5%​ of $400$400​.
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Answer:

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Step-by-step explanation:

7 0
2 years ago
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for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b
marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

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Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

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Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4        

7 0
1 year ago
41:41
Minchanka [31]

Answer:

Answer: B

Step-by-step explanation:

just solve keep up learning!

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3 years ago
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