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Oksi-84 [34.3K]
3 years ago
15

Which of these is an example of a literal equation?

Mathematics
2 answers:
RSB [31]3 years ago
5 0

<u>ANSWER</u>

ax-by=k is an example of literal equation.

<u>EXPLANATION</u>

A literal equation is an equation in which letters or variables are used to represent real values.

A literal equation consists of at least two letters or variables.

The first option consists of two variables but it is not an equation. It is just an expression.


The second option is not a literal equation because it consists of only one variable. This is  just a linear equation in one variable. But a literal equation should have at least two variables or letters.

As for the third option, it does not even contain a variable or letter.

77julia77 [94]3 years ago
4 0
Choice D. represents a literal equation
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Answer:

y = lnx/ln12

Step-by-step explanation:

Given the function y = 12^x, to find the inverse of the function, we news to write x as a function of y as shown:

Given y = 12^x

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ln y = ln 12^x

ln y = xln12

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x = lny/ln12

x = ln(y-12)

Replacing y with x and x with y

The inverse of the function will be:

y = lnx/ln12

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Read 2 more answers
In △ABC, AB = 13.2m,
luda_lava [24]

Answer:

(i) ∠ABH  = 14.5°

(ii) The length of AH = 4.6 m

Step-by-step explanation:

To solve the problem, we will follow the steps below;

(i)Finding  ∠ABH

first lets find <HBC

<BHC + <HBC + <BCH  = 180°  (Sum of interior angle in a polygon)

46° + <HBC  + 90 = 180°

 <HBC+ 136°  = 180°

subtract 136 from both-side of the equation

 <HBC+ 136° - 136°  = 180° -136°

 <HBC  = 44°

lets find <ABC

To do that, we need to first find <BAC

Using the sine rule

\frac{sin A}{a} =  \frac{sin C}{c}

A = ?

a=6.9

C=90

c=13.2

\frac{sin A}{6.9} = \frac{sin 90}{13.2}

sin A = 6.9 sin 90  /13.2

sinA = 0.522727

A = sin⁻¹ ( 0.522727)

A ≈ 31.5 °

<BAC  = 31.5°

<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)

31.5° +<ABC + 90° = 180°

<ABC  + 121.5°  = 180°

subtract 121.5° from both-side of the equation

<ABC  + 121.5° - 121.5°  = 180° - 121.5°

<ABC = 58.5°

<ABH = <ABC - <HBC

           =58.5° - 44°

            =14.5°

∠ABH = 14.5°

(ii) Finding the length of AH

To find length AH, we need to first find ∠AHB

<AHB + <BHC = 180°  ( angle on a straight line)

<AHB + 46° = 180°

subtract 46° from both-side of the equation

<AHB + 46°- 46° = 180° - 46°

<AHB  = 134°

Using sine rule,

\frac{sin 134}{13.2}  = \frac{sin 14.5}{AH}

AH = 13.2 sin 14.5 / sin 134

AH≈4.6 m

length AH = 4.6 m

8 0
3 years ago
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