A function is differentiable if you can find the derivative at every point in its domain. In the case of f(x) = |x+2|, the function wouldn't be considered differentiable unless you specified a certain sub-interval such as (5,9) that doesn't include x = -2. Without clarifying the interval, the entire function overall is not differentiable even if there's only one point at issue here (because again we look at the entire domain). Though to be fair, you could easily say "the function f(x) = |x+2| is differentiable everywhere but x = -2" and would be correct. So it just depends on your wording really.

5 0

3 years ago

A parabola can be drawn given a focus of (-5, -4)(−5,−4) and a directrix of y=-6y=−6. Write the equation of the parabola in any

lord [1]

Answer:

$\displaystyle \large{y=\dfrac{x^2}{4} + \dfrac{5x}{2} + \dfrac{5}{4}}$

Step-by-step explanation:

Given:

Focus = (-5,-4)
Directrix = -6

To find:

Parabola Equation

Locus of Parabola (Upward/Downward)

$\displaystyle \large{\sqrt{(x-a)^2+(y-b)^2} = |y-c|}$

Where:

(a,b) = focus
c = directrix

Hence:

$\displaystyle \large{\sqrt{(x+5)^2+(y+4)^2}=|y+6|}$

Cancel square root by squaring both sides as we get:

$\displaystyle \large{(x+5)^2+(y+4)^2=(y+6)^2}$

Solve for y-term:

$\displaystyle \large{(x+5)^2=(y+6)^2-(y+4)^2}\\\displaystyle \large{x^2+10x+25=y^2+12y+36-y^2-8y-16}\\\displaystyle \large{x^2+10x+25=4y+20}\\\displaystyle \large{x^2+10x+5=4y}\\\displaystyle \large{y=\dfrac{x^2}{4} + \dfrac{5x}{2} + \dfrac{5}{4}}$

4 0

1 year ago

Which function represents the data in the table?

77julia77 [94]

Answer:

Pretty sure it's D

Step-by-step explanation:

3 0

3 years ago