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alisha [4.7K]
3 years ago
6

6b^2+8b-10=0 please show how to do work

Mathematics
2 answers:
Len [333]3 years ago
5 0
Determine # of solutions using discrimination
D = b^2 - 4 ac
D=8^2 - 4 x 6 x ( -10 )
D = 304
D > 0
The quadratic equation has 2 real solutions
balu736 [363]3 years ago
4 0

<em>Greetings from Brasil....</em>

Let's solve this 2nd degree equation.

6b² + 8b - 10 = 0       dividing all terms by 2

3b² + 4b - 5 = 0         applying the baskara formula

Δ = 4² - 4 · 3 · (- 5)

Δ = 76

b = (- 4 ± √76)/6      so

<h2>b' = (- 4 + √76)/6</h2><h2>b'' = (- 4 - √76)/6</h2>

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Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
3 years ago
Read 2 more answers
A high- speed elevator can rise 500 feet in 30 seconds. Which expression represents the rate, in feet per minute, of the elevato
maria [59]
The expression is r = 500 • 2, where “r” represents the rate.
5 0
3 years ago
Is 18-35 an expression or an equation
allsm [11]

Answer:

It is an expression

Step-by-step explanation:

An equation needs to have an equal sign in it and 18-35 doesn't  have an equal sign

Hope this helps!! :)

6 0
3 years ago
Read 2 more answers
Find the third side in simplest radicle form: 8 and 34
zysi [14]

Answer:

7\sqrt{2}

Step-by-step explanation:

\sqrt{98} = 7\sqrt{2}

5 0
3 years ago
A rectangle has a perimeter of 56 in. The length is four more than the width. What are the length and width of the rectangle
Aleks04 [339]

Answer:

Width = 12 in

Length = 16 in

Step-by-step explanation:

Let, the Width of the rectangle = w in

Now, the length of the rectangle = (w + 4) in

Now, Perimeter = 56 in

Also, we know that

Perimeter of the Rectangle = 2 (Length +Width)

or, 2 (Length +Width) = 56

⇒ 2(w + 4 +w) = 56

or, 4w =56 -8

width  = 12 in

So, Length = w + 4 = 12 + 4 = 16 in

7 0
3 years ago
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