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2 years ago

Give the slope between the points (-2,3) (-5, -9)

Mathematics

2 answers:

RUDIKE [14]2 years ago

7 0

The slope is 4. i hope this helped:)

valentina_108 [34]2 years ago

4 0

M = (-9 - 3) / (-5 - -2)
m = -12 / -3
m = 4

The slope is 4.

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Evaluate the expression. 1/2 x (4+8)

Elanso [62]

Answer:

Hey there!

1/2 x (4+8)

1/2 x (12)

Hope this helps :)

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2 years ago

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② The complement of an angle. is 10 more than 3 times the angle. Find both

Mrac [35]

Let x be the angle. The complement is 3x + 10. The sum of two complementary angles is 90. So,
x + 3x + 10 = 90
4x + 10 = 90
4x = 80
x = 20
Plug x into the complement
3(20) + 10 = 70

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2 years ago

What is the mean score Score 90 80 70 60

cupoosta [38]

Answer:

Step-by-step explanation:

Four scores.... add them together and divide by four

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1 year ago

What is the slope of the graph of 4 x + 8 y = 11?

Karolina [17]

Answer:

B -1/2

Step-by-step explanation:

4x+8y = 11

We need to get the equation in the slope intercept form

y = mx+b where m is the slope and b is the y intercept

Subtract 4x from each side

4x-4x+8y = -4x+11

8y = -4x+11

Divide by 8

8y/8 = -4x/8 +11/8

y = -1/2x +11/8

The slope is -1/2 and the y intercept is 11/8

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2 years ago

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Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

2 years ago