Proof.
For two dice, the number of favorable cases is 5: (6, 2);(5, 3);(4, 4);(3, 5);(2, 6); so the
probability is 5/36 =
30/216
For three dice, the number of favorable cases is 21: (5, 2, 1), (4, 3, 1) counted with all permutations
(so 6 2 = 12), and (1, 1, 6), (2, 2, 4), (3, 3, 2), counted with the distinct permutations (so
3 3 = 9). The probability is 21/216
So the more likely case is for two dice.
Simplifying
-16 + 23 (-4) + -3
Multiply 23 x -4
Add -16 + -92=-108
Add -108-3= -111 <------Answer
Answer:
-39 is less than or equal to C
Step-by-step explanation:
39 is greater or equal to -C
-39 is less than or equal to C
I did another one just like this about an hour ago. I did it the elegant, tedious way,
and it took about 2 feet of screen. Then I realized there was a totally bourgeois but
easy way to do it. For 5 points, I'll give you the method for the masses:
List all the possible pairs of digits that add up to 9, along with their flips:
18 . . . . . 81
27 . . . . . 72
36 . . . . . 63
45 . . . . . 54
Do you see any pair that are different by 27 ?
How about 36 and 63 ?
So the original number is 63, and when you flip it, it becomes 36, which is 27 less.