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frozen [14]
3 years ago
9

Please help first answer will get brainliest!

Mathematics
1 answer:
scZoUnD [109]3 years ago
5 0

Answer: -10

Step-by-step explanation: From the start of the equation, we know it must factor to something like (3m + x)(n+y), because the first term must be 3mn. Now, for the next term to be -6n, y must be -2, and for the third term to be 5n, x must be positive 5. So we end up with (3m+5)(n-2). If we factor this out, we get 3mn-6m+5n-10, meaning the final term is -10.

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Anyone know how to do this
Anton [14]

let

(hypotenuse ) c = 10 in

(perpendicular) a = 8 in

(base) b =?

By using Pythagoras theorem

c^2= a^2+b^2

(10)^2 = (8)^2 +(b)^2

100 = 64 +(b)^2

100- 64 = (b)^2

36 = (b)^2

√36 = b

6 = b

hence b= 6 in

3 0
2 years ago
(1008.5)(2) pleasee helpp
nikdorinn [45]

Answer:

2,016.4

Step-by-step explanation:

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2 years ago
What is the name for a model that you cannot touch but gives you a mental image of how something works? a. a physical model b. a
likoan [24]
I think its C. conceptual model 
8 0
3 years ago
Read 2 more answers
Use the function s=8r+14 to find the value of s when r=3.
Phantasy [73]

Answer: s= 38


Step-by-step explanation:

S=8r+14 or S=8(3)+14

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4 0
3 years ago
Read 2 more answers
In ΔNOP, n = 910 inches, o = 110 inches and p=820 inches. Find the measure of ∠P to the nearest degree.
Sophie [7]

Given:

In ΔNOP, n = 910 inches, o = 110 inches and p=820 inches.

To find:

The measure of ∠P to the nearest degree.

Solution:

According to the law of cosine:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using law of cosine in triangle NOP, we get

\cos P=\dfrac{n^2+o^2-p^2}{2no}

Putting the given values, we get

\cos P=\dfrac{(910)^2+(110)^2-(820)^2}{2(910)(110)}

\cos P=\dfrac{828100+12100-672400}{200200}

\cos P=\dfrac{167800}{200200}

\cos P=0.83816

Taking cos inverse on both sides, we get

P=\cos^{-1}(0.83816)

P=(33.05367)^\circ

P\approx 33^\circ

Therefore, the measure of ∠P is 33°.

8 0
2 years ago
Read 2 more answers
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