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2 years ago

Factor 2x2c2 + 3xc2 − 35c2. Show your work.

Mathematics

2 answers:

Feliz [49]2 years ago

6 0

$\\ \sf\longmapsto 2x^2c^2+3xc^2-35c^2$

Take c^2 common

$\\ \sf\longmapsto c^2(2x^2+3x-35)$

Factor the brackets

$\\ \sf\longmapsto c^2(2x^2+10x-7x-35)$

$\\ \sf\longmapsto c^2(2x(x+5)-7(x+5))$

$\\ \sf\longmapsto c^2(2x-7)(x+5)$

Dimas [21]2 years ago

3 0

Answer:

c²(x + 5)(2x - 7)

Step-by-step explanation:

2x²c² + 3xc² - 35c² =
c²(2x² + 3x - 35) =
c²(2x² + 10x - 7x - 35) =
c²(2x(x + 5) - 7(x + 5)) =
c²(x + 5)(2x - 7)

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Ok need help this is the question :Use the Pythagorean theorem to write an equation for the distance Jane's trainer bikes.

IRINA_888 [86]

Answer:

Jane traveled 8 miles farther then her trainer

Step-by-step explanation:

The Pythagora's Theorem

In any right triangle, the square of the measure of the hypotenuse is the sum of the squares of the legs. This can be expressed with the formula:

$c^2=a^2+b^2$

Where

c = Hypotenuse or largest side

a,b = Legs or shorter sides

Jane's path from the Health Club to the end of her route describes two sides of a right triangle of lengths a=16 miles and b=12 miles.

Her total distance traveled is 16 + 12 = 28 miles

Her trainer goes directly from the Health Club to meet her through the hypotenuse of the triangle formed in the path.

We can calculate the length of his route as:

$c=\sqrt{16^2+12^2}$

$c=\sqrt{256+144}=\sqrt{400}=20$

c = 20 miles

The difference between their traveled lengths is 28 - 20 = 8 miles

Jane traveled 8 miles farther then her trainer

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2 years ago

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bazaltina [42]

Answer:

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Step-by-step explanation:

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3 years ago

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Genrish500 [490]

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3 years ago

Given: triangle ABC,

Andrei [34K]

The value of AD in triangle ABC is approximately 9 cm.

BC = 6cm

Using trigonometric ratio for triangle CBD

sin 60° = opposite / hypotenuse

0.86602540378 = DC / 6

cross multiply

DC = 6 × 0.86602540378

DC = 5.19615242271