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never [62]
4 years ago
6

F(x)=2/x and g(x)=2/x what is f(g(x))

Mathematics
1 answer:
Reika [66]4 years ago
5 0

Answer:

f(g(x)=x

Step-by-step explanation:

Put g(x)=2/x in the place of "x" in f(x)

f(2/x)=2/(2/x)

Cancel 2 with 2 and remaining is 1/(1/x) which is "x"

f(g(x)=x

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Evaluate s(t)=∫t−[infinity]||r′(u)||du for the bernoulli spiral r(t)=⟨etcos(8t),etsin(8t)⟩. It is convenient to take −[infinity]
sveta [45]

\vec r(t)=\langle e^t\cos8t,e^t\sin8t\rangle

\|\vec r'(t)\|=\sqrt{(e^t(\cos8t-8\sin8t))^2+(e^t(\sin8t+8\cos8t))^2}=e^t\sqrt{(\cos8t-8\sin8t)^2+(\sin8t+8\cos8t)^2}

\implies\|\vec r'(t)\|=e^t\sqrt{65}

Then

s(t)=\displaystyle\sqrt{65}\int_{-\infty}^te^u\,\mathrm du=\sqrt{65}e^t

3 0
3 years ago
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monitta
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4 0
3 years ago
Read 2 more answers
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kotykmax [81]

Answer:

The answer is D. You divide the shape into 3 rectangles.

Step-by-step explanation:

3 0
3 years ago
Write the equation of a line in slope intercept form that is perpendicular to the line y = –4x and passes through the point (2,
Gnesinka [82]

1. If the line that we are searching for is perpendicular to the line y = -4x, this means that the gradient of our line and the gradient of the perpendicular line will multiply to give -1. Thus if we call the gradient of our line m, then:

m*(-4) = -1

-4m = -1

m = 1/4

2. Since we know that m = 1/4 and we have a point (2,6) on our line, we can use the formula y - y1 = m(x - x1) to find the equation of our line, where (x1, y1) is the coordinates of a point on the line. Thus:

y - y1 = m(x - x1)

y - 6 = (1/4)(x - 2)

y - 6 = (1/4)x - 2/4 (Expand (1/4)(x - 2))

y = (1/4)x - 1/2 + 6 (Simplify 2/4 and add 6 to each side)

y = (1/4)x + 11/2 (Evaluate -1/2 + 6)

Slope-intercept form is given by y = mx + c. As our equation is already in this form, there is nothing more to do. Thus, the answer is y = (1/4)x + 11/2

6 0
3 years ago
Write an expression in simplest form for the perimeter of a right triangle with leg lengths of 3a cubed and 4a cubed
Over [174]

Answer:

106.4622 a^{3}

Step-by-step explanation:

Given the information:

  • A right triangle
  • Leg lengths of (3a)^{3} and (4a)^{3}

Use the pytagon theory to find the hypotenuse of the triangle

a^{2}  + b^{2}  = c^{2}

<=>((3a)^{3}) ^{2}  + ((4a)^{3}) ^{2}  = c^{2}

<=>(3a)^{6} + (4a)^{6} = c^{2}  

<=> c^{2}  = 4285a^{6}

Take the square root of both sides

<=> c = 69.4622 a^{3}

=> expression in simplest form for the perimeter of a right triangle is:

(3a)^{3} + (4a)^{3} + 69.4622 a^{3}  

= 27a^{3}  + 64a^{3}  + 69.4622 a^{3}  

= 106.4622 a^{3}

8 0
3 years ago
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