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4 years ago

How can sums and differences of cubes be identified for factoring?

Mathematics

1 answer:

yan [13]4 years ago

5 0

Answer:

Step-by-step explanation:

The sum of two perfect cubes breaks down into two factors, the first is the sum of their cube roots, and the second is made up of the square of the first root minus the product of both roots plus the square of the second root.

The difference of two perfect cubes is decomposed into two factors, the first is the difference of their cube roots, and the second is made up of the square of the first root plus the product of both roots plus the square of the second root.

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Simplify the following boolean expression (A+B) (A+B)

vichka [17]

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$(A + B)(A + B) =$

${A}^{2} + 2AB + {B}^{2}$

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3 years ago

Please i really need help on this.

Studentka2010 [4]

Answer:

it is C

Step-by-step explanation: please brainliest

6 0

3 years ago

Please help me ASAP!!

choli [55]

Answer:

r = -4

Step-by-step explanation:

If M is the midpoint of DE, that would mean that the distance from M to D and M to E would be the same.

This creates the equation 1-8r=13-5r.

Now it's just simple algebra.

You add 8r to both sides, creating 1=13+3r. Then, you subtract 13 from both sides, getting 3r=-12. Dividing both sides by 3 and solving for r, you get r=-4.

Checking our answer, you see that 1-8(-4)=1-(-32)=1+32=33, and 13-5(-4)=13-(-20)=13+20=33.

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3 years ago

A computer manufacturer releases a new laptop model. The total sales of this computer can be modeled by the function S(t)=75/1+5

maksim [4K]

The answer is 23445.90

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4 years ago

Read 2 more answers

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

7 0

3 years ago