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tatyana61 [14]
3 years ago
11

Jayne is taking two AP classes and three regular classes. Her AP classes count twice as much as her regular classes in her GPA.

Each A is worth 4 points, Bs are worth 3 points, Cs are worth 2 points, and Ds are worth 1 point. what is Jayne's GPA?
AP English - C
AP Govt. - B
Algebra 2 - B
Spanish - D
Physics - A

A. 2.6
B. 3.6
C. 1.9
D. 3.0
Mathematics
1 answer:
miv72 [106K]3 years ago
8 0
Frist off what the heck is GPA second I think it's D. 3.0
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Sean and Kyle have 26 dollars between them. If Sean has 8 more dollars than Kyle, how much money does Kyle have, in dollars?
vredina [299]

Answer: 9$

Step-by-step explanation:

kyle has x dollars. Sean has x+8 dollars. They equal 26. 2x+8=26

2x=18

x=9

7 0
3 years ago
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For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va
Black_prince [1.1K]

Answer:

3 solutions:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is tan(\frac{\theta}{2}) so let's focus on that part of the equation first.

We know that:

tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}

therefore:

cos(\frac{\theta}{2})\neq0

so we need to find the angles that will make the cos function equal to zero. So we get:

cos(\frac{\theta}{2})=0

\frac{\theta}{2}=cos^{-1}(0)

\frac{\theta}{2}=\frac{\pi}{2}+\pi n

or

\theta=\pi+2\pi n

we can now start plugging values in for n:

\theta=\pi+2\pi (0)=\pi

if we plugged any value greater than 0, we would end up with an angle that is greater than 2\pi so,  that's the only angle we cannot include in our answer set, so:

\theta\neq \pi

having said this, we can now start solving the equation:

tan(\frac{\theta}{2})=sin(\theta)

we can start solving this equation by using the half angle formula, such a formula tells us the following:

tan(\frac{\theta}{2})=\frac{1-cos(\theta)}{sin(\theta)}

so we can substitute it into our equation:

\frac{1-cos(\theta)}{sin(\theta)}=sin(\theta)

we can now multiply both sides of the equation by sin(\theta)

so we get:

1-cos(\theta)=sin^{2}(\theta)

we can use the pythagorean identity to rewrite sin^{2}(\theta) in terms of cos:

sin^{2}(\theta)=1-cos^{2}(\theta)

so we get:

1-cos(\theta)=1-cos^{2}(\theta)

we can subtract a 1 from both sides of the equation so we end up with:

-cos(\theta)=-cos^{2}(\theta)

and we can now add cos^{2}(\theta)

to both sides of the equation so we get:

cos^{2}(\theta)-cos(\theta)=0

and we can solve this equation by factoring. We can factor cos(\theta) to get:

cos(\theta)(cos(\theta)-1)=0

and we can use the zero product property to solve this, so we get two equations:

Equation 1:

cos(\theta)=0

\theta=cos^{-1}(0)

\theta={\frac{\pi}{2}, \frac{3\pi}{2}}

Equation 2:

cos(\theta)-1=0

we add a 1 to both sides of the equation so we get:

cos(\theta)=1

\theta=cos^{-1}(1)

\theta=0

so we end up with three answers to this equation:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

7 0
2 years ago
Which of the following shows the least expensive unit price? *
Ilia_Sergeevich [38]
B/ 4 oranges for $1.52 I think.
8 0
3 years ago
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Determine which relation is a function.
klemol [59]
A is the correct choice.

This is based on the vertical line test. If you were to draw an imaginary vertical line on the graph, it would only intersect the graph at one point, which proves that all x values are different (a function).
7 0
3 years ago
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PLEASE ANSWER QUICKLY AS POSSIBLE WILL GIVE BRAINLYEST TO FIRST CORRECT
Tems11 [23]

Answer:

Soln:

Step-by-step explanation:

Here,

Base(b) =9

Opposite/Perpendicular (p)= x

Hypotenus (h) = 24

We know,

(p)^2 = (h)^2 - (b)^2

(x)^2 = (24)^2 - (9)^2

x^2 = 576 - 81

x^2 = 495

x = root under 495

6 0
2 years ago
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