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4 years ago

What logarithmic function represents the data in the table?

Mathematics

2 answers:

alina1380 [7]4 years ago

8 0

216 =6^3
1,296 = 6^4
7,776 = 6^5
x = 6^f(x)
log x = log 6^f(x) = f(x)log 6
f(x) = log x / log 6 = $log_6x$

lubasha [3.4K]4 years ago

3 0

The correct answer among the choices provided is the fourth option. The logarithmic function f(x)=log(base 6)x represents the data in the table. Log is the value that one can get to express a number to a certain power. It is solved through finding the pattern using the given values,
6^3 = 216
6^4 = 1296
6^5 = 7776

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(2+4i) + (9+10i) = (2+9) + (4i+10i)

HACTEHA [7]

11+14i=11+14

The answer is 0

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3 years ago

Help please with explain so for further questions like this

Yakvenalex [24]

Rmember (a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)this is just alot of busy work

find f+g first then find f-g

f+g=(x-4)/(x+9)+(x-9)/(x+4)
make denomenator the same
multiply left one by (x+4)/(x+4) and right one by (x+9)/(x+9)
[(x-4)(x+4)]/[(x+9)(x+4)]+[(x-9)(x+9)]/[(x+9)(x+4)]
[x²-16]/[(x+9)(x+4)]+[x²-81]/[(x+9)(x+4)]
[x²+x²-16-81]/[(x+9)(x+4)]
[2x²-97]/[(x+9)(x+4)]

now f-g
[x²-16]/[(x+9)(x+4)]-[x²-81]/[(x+9)(x+4)]
[x²-x²-16+81]/[(x+9)(x+4)]
[65]/[(x+9)(x+4)]

now we got
$\frac{ \frac{2x^2-97}{(x+9)(x+4)} }{ \frac{65}{(x+9)(x+4)} }$
invert and multiply
$(\frac{2x^2-97}{(x+9)(x+4)})(\frac{(x+9)(x+4)}{65})$
$\frac{2x^2-97}{65}$

2nd option

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3 years ago

Which unit rate is the lowest price per ounce?

klasskru [66]

Answer:

Choice A

Step-by-step explanation:

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2 years ago

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PLEASE ANSWER RIGHT AWAY

Tcecarenko [31]

Answer:

The sequence 3 , 4 , 6 , 10 , 18 described by the 2nd term is t2 = 4 and recursive definition is tn+1 = 2 tn - 2 ⇒ 4th answer

Step-by-step explanation:

* Lets revise the recursive formula

1. Determine if the sequence is arithmetic (Do you add, or subtract, the

same amount from one term to the next?)

2. Find the common difference. (The number you add or subtract.)

3. Create a recursive formula by stating the first term, and then stating

the formula to be the previous term plus the common difference.

a1 = first term;

an+1= an + d

- Where:

# a1 = the first term in the sequence

# an = the nth term in the sequence

# an+1 = the term after the nth term

# n = the term number

# d = the common difference.

* Now lets solve the problem

∵ The recursive definition is tn+1 = 2 tn - 2 and t2 = 4

- Look to the answer we have three answer with second term = 4,

1st , 2nd and 4th

- Lets find the 1st term

∵ t2 = 2 t1 - 2

∵ t2 = 4

∴ 4 = 2 t1 - 2 ⇒ add 2 to the both sides

∴ 6 = 2 t1 ⇒ divide the two sides by 2

∴ t1 = 3

- We have two answer with first term = 3, 2nd and 4th answers

* Lets find the third term

∵ t3 = 2 t2 - 2

∵ t2 = 4

∴ t3 = 2 (4) - 2 = 8 - 2 = 6

∴ The 4th answer has the third term = 6

* The 4th sequence 3 , 4 , 6 , 10 , 18 described by the 2nd term is

t2 = 4 and recursive definition is tn+1 = 2 tn - 2

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3 years ago

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IRINA_888 [86]

Answer:

i think maybe D

Step-by-step explanation:

Normally a equation has to have an equal sign and all the numbers add up

4 0

3 years ago

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