Answer:
A) T and R
B) <SQR or <RQS
C) Q
Step-by-step explanation:
A) The sides of a angle are the end points which are T and R in this case.
B) Angle 2 has S and R and its end points. And the vertex which is Q is always in the middle, so the angle is <SQR and <RQS
Correct answer is: F(x)=-x^2-3
Step-by-step explanation:
We are given a function:
The graph of is also shown in the given question figure.
It is a parabola with vertex at (0,0).
Sign of is positive, that is why the parabola opens up.
General equation of parabola is given as:
Here, in G(x), a = 1
Vertex (h,k) is (0,0).
As seen from the question figure,
The graph of F(x) opens down that is why it will have:
Sign of as negative. i.e.
And vertex is at (0,-3)
Putting the values of a and vertex coordinates,
Hence, the equation of parabola will become:
Using Pythagorean theorem, we can justify our answer.
if c^2 = a^2 + b^2 then triangle is right one,
if c^2 > a^2 + b^2 then triangle is obtuse and
if c^2 < a^2 + b^2 then triangle is acute triangle.
Here a=8, b=11 and c=16
Put these values in the equation
16^2 = 8 ^2 + 11^2
256 = 64 +121
256> 185
So here c^2 > a^2 + b^2 Which means triangle is obtuse triangle.
Answer: Obtuse Triangle
Just put 3.150 lol that what I did
Answer:
0.927
Step-by-step explanation:
add then round the last digit (it doesnt matter if it is a decimal number or not).
