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seropon [69]
3 years ago
5

If a 100-pound block of ice is placed on an inclined plane that makes an angle of 35° with the horizontal, how much friction for

ce will be required to keep it from sliding down the plane? Choose the equation that could be used to solve the problem if x represents the force required to keep the block from sliding down the plane.
Mathematics
1 answer:
alexdok [17]3 years ago
6 0

Answer:

F = 100(.5736)  

= 57.36 lbs. (rounded off to 2 decimal places)  

2) sin60 = .866  

F = 18(.866)  

= 15.59 lbs. (rounded off to 2 decimal places)

Step-by-step explanation:

F = friction

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D) Vivek is 30 years younger than his father. After 10 years their ages will be in the ratio 1:2. Find their present ages.​
tangare [24]

Answer:

I think Vivek is 20 and his father is 50

Because 30 + 30 equals 60 as he has to be half his age he'll be 30 but that's in 10 years time. you just subtract 30 and 60 by 10 and you'll get 20 and 50

6 0
3 years ago
Read 2 more answers
Plz answer me will mark as brainliest and will reported if wrong answer ​
Sergeu [11.5K]

Answer:

1,2,3

18=8×1 =

Step-by-step explanation:

Plz mark as brainliest and follow me plz

6 0
3 years ago
Solve for j show work<br> 8j-5+j=67
andrew11 [14]

Answer:

8

Step-by-step explanation:

8j-5+j=67

8J+j

9J-5=67

  +5   +5

9J=72

/9   /9

j=8

If this helps please put brainliest

8 0
3 years ago
A very large number of college men were asked what they thought their ideal weight was. A five number summary of the response (i
Lilit [14]

Answer:

Nearly 48.78% of the men  gave a response that falls in the interval 155 to 195 pounds

Step-by-step explanation:

Given that a very large number of college men were asked what they thought their ideal weight was.

A five number summary of the response (in pounds) follows:

Median 175

Quartiles 155 196

Extremes 123 225

This implies that 25th percentile is 155 and 75th percentile is 196

This can be interpreted as approximately 50% of men lie between 155 and 196 pounds.

Since 195 is very near to 195, we can say approximately

i.e. 41 difference = 50%

40 difference = \frac{40*50}{41} \\=48.78

Nearly 48.78% of the men  gave a response that falls in the interval 155 to 195 pounds

4 0
3 years ago
Let F be the event that a student is enrolled in a finance course, and let S be the event that a student is enrolled in a statis
Inessa [10]

Answer:

0.375

Step-by-step explanation:

Given that F is the event that a student is enrolled in a finance course, and let S be the event that a student is enrolled in a statistics course.

It is known that 40% of all students are enrolled in a finance course and 35% of all students are enrolled in statistics. Included in these numbers are 15% who are enrolled in both statistics and finance.

P(F) = 0.40:  P(S) = 0.35:  P(FS) = 0.15

A student is randomly selected, and it is found that the student is enrolled in finance.

Probability that this student is also enrolled in statistics/ student is enrolled in finance.

= \frac{P(FS)}{P(F)} \\=\frac{0.15}{0.40} \\=0.375

(Using conditional probability formula)

5 0
3 years ago
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