Answer:
1. 1,800
2. 500
3. 36,500.03
4. 86.3
Step-by-step explanation:
If you need me to show the work comment and I'll send it to you.
Answer:
![b\sqrt[n]{a}](https://tex.z-dn.net/?f=b%5Csqrt%5Bn%5D%7Ba%7D)
Step-by-step explanation:
Answer: Choice C
The first inequality is 
The second inequality is 
Replace x with whatever letter your teacher is using
=========================================================
Let x be the number of cans collected on week 3
Add this to the previous totals (for weeks 1 and 2) to get 124 + 121 + x. I'm going to leave this as is and not simplify. This is so the answer matches up. This total must be greater than or equal to 400, meaning 124+121+x can be 400 or larger.
124+121+x >= 400
245+x >= 400 .... combine like terms
x >= 400-245 .... subtract 245 from both sides
x >= 155
So you need to collect at least 155 cans for the third week so that you'll have at least 400 cans total.
Answer:53 dresses
Step-by-step explanation:
First of all..if one kid required 2 1/4m of cloth,what about 119 1/4m of cloth?
So u take 119 1/4m of cloth and divide it by 2 1/4m of cloth.
Then change the mixed numbers into improper fractions.
So the question will be 477/4 m divided by 9/4 m.
The second improper fraction (9/4)m will be reciprocated to be (4/9)m.
Afterwards,take 477/4 m and multiply it by 4/9 m.
The result will be 53 dresses.