The carbon 14 left from this animal is 3 grams of 24 grams which is: 3g/24g= 1/8 times of its original mass. Then, the age of the animal fossil would be:
final weight= initial weight * (1/2) ^ time/half-live
1/8 initial weight = initial weight * (1/2) ^ time/half-live
log2 1/8= log2 (1/2) ^ time/half-live
-3= -time/half-live
time= -3 * -(half-live)
time= 3 half-live
If the half-live is 5730 years, the age would be: 3* 5730= 17.190 years.
The answer is B: proteins and lipids.
Also carbohydrates
<span>In humans, oogenesis
in comparison to spermatogenesis is different in that the temperature they have.
Female puberty typically occurs much later than the age of male puberty oocyte
production works best at cooler temperatures than those that support
spermatogenesis oogenesis continues throughout life, but spermatogenesis
typically ends.</span>
It’s b chromosomes because the cell nucleus contains the majority of cells genetic material in the form of multiple linear DNA molecules
