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dimaraw [331]
3 years ago
14

What is the area of a sector with radius 4 and an angle of 18°? Use 3.14 for p...

Mathematics
1 answer:
LiRa [457]3 years ago
4 0
\dfrac{18^o}{360^o}=\dfrac{1}{20}\\r=4\\\\A=\dfrac{1}{20}\cdot\pi\cdot4^2=\dfrac{1}{20}\pi\cdot16=\dfrac{16}{20}\pi=\dfrac{4}{5}\pi=0.8\pi\approx0.8\cdot3.14=2.512\\\\Answer:\boxed{A=2.512}
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I WILL GIVE BRAINLIEST TO FIRST RIGHT ANSWER
nikitadnepr [17]

Answer:

  • 5.7 m/s

Step-by-step explanation:

<u>Approximate rate of change:</u>

  • (25.1 - 2.3)/(4 - 0) =
  • 22.8/4 =
  • 5.7 m/s
5 0
3 years ago
Did I do this correctly?
butalik [34]

6/x= -2/18

Cross multiply. ( Multiply the numerators together ) . ( Multiply the denominators together (.

6*18= - 2*x

108= -2x

Divide by -2 for 108 and -2x

108/-2= -2x/2

x= -54

Answer: x= -54

6 0
3 years ago
What is the solution to the inequality?<br><br><br> -2x-4 less than or equal to 11
Rashid [163]

Answer:

x ≤  \frac{-15}{2}

Step-by-step explanation:

So first you would start by getting rid of the -4. To get rid of -4, you would need to + 4 on each side leaving you with -2x ≤ 15. Now you need to get rid of -2 from x so that would convert equation to x ≤  \frac{-15}{2}. Hoped it helped!

⭐ Answered by Foxzy0⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

4 0
3 years ago
Find the standard form of the equation of the circle with endpoints of a diameter at the points (3,8) and (-7,2)
poizon [28]

(x+2)^{2}+(y-5)^{2}= 34

The equation of a circle in standard form is

(x-a)^{2}+(y-b)^{2}=r^{2}

where (a , b) are the coordinates of the centre and r is the radius

The centre is at the midpoint of the endpoints and the radius is the distance from the centre to either of the 2 endpoints

Using the midpoint formula

midpoint = [\frac{1}{2}(xx_{1}+x_{2}, \frac{1}{2}(y_{1}+y_{2}

where (x_{1},y_{1}=(3,8) and (x_{2},y_{2}=(-7,2)

centre = (\frac{1}{2}(3-7),\frac{1}{2}(8+2)) = (-2,5)

Calculate r using the distance formula

r = √(x_{2}-x_{1})²+(y_{2}-y_{1})²)

= √((3+2)²+(8-5)²) = √(25+9) = √34 ⇒ r² =(√34)² = 34

equation of circle is : (x+2)²+(y-5)² = 34


8 0
3 years ago
A scale for a scale drawing is 17 cm:1 mm. Which is larger, the actual object or the scale drawing?
Dvinal [7]

9514 1404 393

Answer:

  the scale drawing is larger

Step-by-step explanation:

The scale tells you that ...

  17 cm on the scale drawing represent 1 mm on the actual object.

17 cm is larger than 1 mm, so the scale drawing is larger.

5 0
3 years ago
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