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cluponka [151]
2 years ago
9

(w+6)(w+7) how to solve

Mathematics
2 answers:
Makovka662 [10]2 years ago
8 0
(w+6)(w+7) = 0

w(w) + w(7) + 6(w) + 6(7) = 0
w² + 7w + 6w + 42 = 0
w² + 13w + 42 = 0

w + 6 = 0
w = -6
<span>w² + 13w + 42 = 0
</span>-6² + 13(-6) + 42 = 0
36 - 78 + 42 =
78 - 78 = 0
0 = 0

w + 7 = 0
w = -7

w² + 13w + 42 = 0
-7² + 13(-7) + 42 = 0
49 - 91 + 42 = 0
91-91 = 0
0=0
Wewaii [24]2 years ago
6 0
(w+6)(w+7)
= w^2+ 7w+ 6w+ 6*7
= w^2+ (7w+ 6w)+ 42 (combine like terms)
= w^2+ 13w+ 42

The final answer is w^2+ 13w+ 42~
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If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure &amp; the perimeter of triangle ABC.
harina [27]

Answer:

Perimeter = 38.6

Step-by-step explanation:

Given

A\ B = 13

B\ F = 9

F\ C = 5.6

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

Perimeter = A B + B\ C + A\ C

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

B\ C^2 = B\ F^2 + F\ C^2

Substitute values for BF and FC;

B\ C^2 = 9^2 + 5.6^2

B\ C^2 = 81 + 31.36

B\ C^2 = 112.36

B\ C^2= \sqrt{112.36

B\ C = 10.6

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

A\ B^2 = B\ F^2 + A\ F^2

Substitute values for B F and A B;

13^2 = 9^2 + A\ F^2

169= 81 + A\ F^2

A\ F^2 = 169 - 81

A\ F^2 = 88

A\ F = \sqrt{88

A\ F = 9.4

Since F lies on line A C:

A\ C = A\ F + F\ C

A\ C = 9.4 + 5.6

A\ C = 15.0

Recall that:

Perimeter = A\ B + B\ C + A\ C

Perimeter = 13 + 10.6 + 15.0

Perimeter = 38.6

<em>Hence, the perimeter is 38.6</em>

3 0
3 years ago
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Step-by-step explanation:

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Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent
Reptile [31]

Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

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This question can be Solved by using Venn diagram

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