<em>AB</em> + <em>ACB</em> = <em>A</em> (<em>B</em> + <em>CB</em>) = <em>A</em> (<em>I</em> + <em>C </em>) <em>B</em>
Taking the inverse gives
(<em>A</em> (<em>I</em> + <em>C </em>) <em>B</em>)⁻¹ = <em>B </em>⁻¹ (<em>I</em> + <em>C</em> )⁻¹ <em>A</em> ⁻¹
so the answer is (A)
Answer:
Step-by-step explanation:
Find the number of possible 5-card hands that contain the cards specified. The cards are taken from a standard 52-card deck.
5 red cards.
Ans: 26C5 = 26!/[21!*5!] = 65780
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4 spades and 1 card that is not a spade.
Ans: [13C4*39C1] = 27885
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3 face cards (kings, queens, or jacks) and 2 cards that are not face cards.
Ans: 12C3*40C2 = 171,600
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