All categories

3 years ago

Please Help!!! Given: 5 x − 6 y = 10 . Determine the x value when y has a value of 0 .

Mathematics

2 answers:

natka813 [3]3 years ago

7 0

Hope this helps :).

BaLLatris [955]3 years ago

4 0

Answer:

hmmmm give me a minute..

Step-by-step explanation:

You might be interested in

An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that $a=\frac{F}{m}$

Using the formula

$a=\frac{10}{8}=\frac{5}{4} m/s^2$

We know that

$v=\sqrt{u^2+2as}$

Using the formula

$v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}$

$v=5.02 m/s$

8 0

3 years ago

Which expression is equivalent to .........? ...... ...... ..... .

Alchen [17]

Answer:

first one

2m=1 == 2+m-1+m

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

-4/5 to the power of 2 times -3/50

Crazy boy [7]

=(-4/5)^2 * -3/50
square -4/5 first; remember -4/5^2 is the same as -4/5 * -4/5

=(-4/5 * -4/5) * -3/50
multiply -4 numerators; multiply 5 denominators

=(-4 * -4)/(5 * 5) * -3/50

=16/25 * -3/50
multiply numerators 16 & -3; multiply denominators 25 & 50

=(16 * -3)/(25 * 50)
= -48/1250

simplify by 2
= -24/625 (or -0.0384)

ANSWER: -24/625 (or -0.0384)

Hope this helps! :)

6 0

3 years ago

Read 2 more answers

What is the explicit rule for this sequence? -5, 15, – 45, 135, ...

hoa [83]

Answer:

Step-by-step explanation:

In a geometric sequence, consecutive terms differ by a common ratio. The formula for determining the nth term of a geometric progression is expressed as

an = a1r^(n - 1)

Where

a represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

From the given sequence,

a1 = - 5

r = 15/- 5 = - 3

Therefore, the explicit rule for this sequence is

an = - 5(- 3)^n - 1

4 0

3 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

3 years ago