All categories

3 years ago

what is an equation of the line that passes through the point (-3,-5) and is parallel to the line 2x+3y=15

Mathematics

1 answer:

Mumz [18]3 years ago

7 0

Answer:y=-2x/3+10

Step-by-step explanation:

You might be interested in

Help me with the word problem please

Luda [366]

2.5 hours both plummets will have $100

3 0

3 years ago

Look at this set of 8 numbers:

Nastasia [14]

the mode would change because 83 replaced 99

(idk sorry i wish i could help you but i really dont know)

5 0

3 years ago

Read 2 more answers

Home work.......harrrrrrrrry

mart [117]

Answer:

21 letters.

Step-by-step explanation:

So, what you need to find here is how many letters precede the letter V. You could count the letters, but since V is near to the end of the alphabet, faster way would be to count the letters from behind. We know that the ending streak of the alphabet is ...v, w, x, y, z, and we also know that the english alphabet has 26 letters. So if we count from behind we find that V is fifth letter from behind ( z is 26th, y is 25th, x is 24th, w is 23rd and v is 22nd). Finally, since V is 22nd letter, that means that it is preceded by 21 letter.

7 0

3 years ago

Sam borrowed $4,500 for 2 years and had to pay $630 simple interest at the end of

SSSSS [86.1K]

7% interest rate. He borrowed 4500 for two years. The total amount he had to pay additional in interest was 630. 4500x7% is $315. But since it was 2 years you would do 315x2 which equals 630 which was the amount he ended up paying additional for the two years.

3 0

3 years ago

$36\%$ of the beans in Pythagoras's soup are lentils, and $33\frac13\%$ of those lentils are green. If Pythagoras removes all th

bulgar [2K]

Question is not proper, Proper question is given below;

36% of the beans in Pythagoras's soup are lentils, and 33 1/3% of those lentils are green.

If Pythagoras removes all green lentils from his soup, then x% of the original beans remain. What is x?

Answer:

88% of the original beans remains $(x)$ after removing green lentils.

Step-by-step explanation:

Given:

Let the Original beans be 'n'.

Now given:

36% of the beans in Pythagoras's soup are lentils.

So we can say that;

Amount of lentils = $\frac{36}{100}n=0.36n$

Also Given:

33 1/3% of those lentils are green

Amount of green lentils = $33\frac{1}{3}\%\ \ Or \ \ \frac{100}{3}\%$

Amount of green lentils = $\frac{100}{3}\times 0.36n\times\frac{1}{100}= 0.12n$

Now we need find the percentage of original beans remain after removing green lentils.

Solution:

percentage of original beans remain ⇒ $x\%$

To percentage of original beans remain after removing green lentils we will subtract Amount of green lentils from Original beans and then multiplied by 100.

framing in equation form we get;

$x\%$ = $(n-0.12n)\times 100=88n \ \ \ Or \ \ \ 88\%$

Hence 88% of the original beans remains $(x)$ after removing green lentils.

8 0

4 years ago