3 years ago

The function f is given by f(x)=3x^2+1. What is the average value of f over the closed interval [1,3]?

1 answer:

8 0

You can find the answer using the equation (f(b)-f(a))/(b-a). For this problem, a=1 and b=3.

Then, plug in the numbers and solve:
[(3(3)^2+1)-(3(1)^2+1)]/(3-1)
=(28-4)/2
=12

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sdas [7]

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\\ \quad \\
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yawa3891 [41]

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const2013 [10]

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torisob [31]

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