Answer:
Option 2 - Approximately 24–36 pounds
Step-by-step explanation:
Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.
To find : What range of weights would 99.7% of the dogs have?
Solution :
The range of 99.7% will lie between the mean ± 3 standard deviations.
We have given,
Mean weight of Eskimo dogs is
Standard deviation of Eskimo dogs is
The range of weights would 99.7% of the dogs have,





Therefore, The range is approximately, 24 - 36 pounds.
So, Option 2 is correct.
b=16 , First you multiply 30 by 2 to see what sum you need for the numerator. Then you subtract the 60 that you get by the 12 and get 48. So 3 multiplied by b should give you 48. So you just divide 48 by 3 and get 16.
First convert the rate into a decimal.
8/100=0.08
Next put all those numbers 15,000, 0.08, and 6 into the equation A=P(1+(rt)).
This is how you do it.
A=15,000(1+(0.08*6))
A=15,000(1+0.48)
A=15,000(1.48)
A=22,200
Hi, I'd be glad to help you with this equation!
The answer is (9)
Hope this helps.
Have a great day!
Given function: f(x) = (3x+5)/7
y = f(x) so it's the same as y = (3x+5)/7
Swap every copy of x and y to get x = (3y+5)/7
Solve for y to get....
x = (3y+5)/7
7x = 7*(3y+5)/7
7x = 3y+5
7x-5 = 3y+5-5
7x-5 = 3y
3y = 7x-5
3y/3 = (7x-5)/3
y = (7x-5)/3
So the inverse function is f^(-1)(x) = (7x-5)/3
Answer is choice A