Can you make a triangle with the lengths 10in, 3in and 10in? If so, is it acute, obtuse or right?

Please help me! I will give you Brainlist if you get it right!

Sedaia [141]

Answer:

B

Step-by-step explanation:

find the area of the rectangle and then find the area of the semi circle, then add the 2 together

6 0

3 years ago

(b-2)x= 8

s344n2d4d5 [400]

Answer:

2

Step-by-step explanation:

(2-2)x = 8

(0)x = 8

x = 8/0

no solution

6 0

3 years ago

A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. In a random sam

soldi70 [24.7K]

Answer:

a) $52.8-2.02\frac{3.9}{\sqrt{40}}=51.554$

b) $52.8+2.02\frac{3.9}{\sqrt{40}}=54.046$

c) $52.8-2.71\frac{3.9}{\sqrt{40}}=51.129$

d) $52.8+2.71\frac{3.9}{\sqrt{40}}=54.471$

e) Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =52.8$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=3.9 represent the sample standard deviation

n=40 represent the sample size

a) What is the lower limit of the 95% interval? Give your answer to three decimal places

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=40-1=39$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,39)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$52.8-2.02\frac{3.9}{\sqrt{40}}=51.554$

b) What is the upper limit of the 95% interval? Give your answer to three decimal places

$52.8+2.02\frac{3.9}{\sqrt{40}}=54.046$

So on this case the 95% confidence interval would be given by (51.554;54.046)

c) What is the lower limit of the 99% interval? Give your answer to three decimal places

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,39)".And we see that $t_{\alpha/2}=2.71$

Now we have everything in order to replace into formula (1):

$52.8-2.71\frac{3.9}{\sqrt{40}}=51.129$

d) What is the upper limit of the 99% interval? Give your answer to three decimal places

$52.8+2.71\frac{3.9}{\sqrt{40}}=54.471$

So on this case the 99% confidence interval would be given by (51.129;54.471)

e) Consider the claim that the mean amount of garbage per bin is 54.1985 pounds. Is the following statement true or false? The decision about the claim would depend on whether we use a 95% or 99% confidence interval: True/False

Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

3 0

3 years ago

Adam wishes to have $20 comma 000 available in 18 years to purchase a new car for his son as a gift for his high school graduat

wel

Adam should invest $15516 after 18 years.

<u>Explanation:</u>

Given:

Amount(18) = $20000

Rate of Interest, r = 1.41%

Time, t = 18 years

n = 365 (compounded daily)

General equation of amount that is compounded daily:

$A(t) = A_0(1 + \frac{r}{n} )^n^t$

Solving for A₀:

$A_0 = \frac{A(t)}{(1+\frac{r}{n} )^n^t}$

Substituting the values:

$A_0 = \frac{20000}{(1 + \frac{0.0141}{365})^3^6^5^X^1^8 } \\\\A_0 = \frac{20000}{1.289}\\ \\A_0 = 15516$

Therefore, Adam should invest $15516 after 18 years.

8 0

3 years ago

Given sintheta =7/11 and sectheta is less than 0, find costheta and tantheta

Korvikt [17]

Answer:

Step-by-step explanation:

Sin theta is the ratio of side opposite over hypotenuse of a reference angle situated at the origin in an x-y coordinate plane. If sec theta is negative, then the only quadrant where sin is positive AND sec is negative is quadrant 2. Remember that sec theta is the inverse of cos theta. Puttling our right triangle in QII, the side measuring 7 is across from the angle and the hypotenuse is 11. In order to find the cos theta and tan theta, we need the side adjacent to the angle. Use Pythagorean's Theorem to find the side adjacent.

$11^2=7^2+x^2$ and