Answer:
The answer is 3 1/4
Step-by-step explanation:
I hope this helps! :)
Solve the following system using elimination:
{7 x + 2 y = -19 | (equation 1)
{2 y - x = 21 | (equation 2)
Add 1/7 × (equation 1) to equation 2:
{7 x + 2 y = -19 | (equation 1)
{0 x+(16 y)/7 = 128/7 | (equation 2)
Multiply equation 2 by 7/16:
{7 x + 2 y = -19 | (equation 1)
{0 x+y = 8 | (equation 2)
Subtract 2 × (equation 2) from equation 1:
{7 x+0 y = -35 | (equation 1)
{0 x+y = 8 | (equation 2)
Divide equation 1 by 7:
{x+0 y = -5 | (equation 1)
{0 x+y = 8 | (equation 2)
Collect results:
Answer: {x = -5, y = 8
Answer:
D. QR.
Step-by-step explanation:
1) in ΔQRS the side QR is opposite the angle S (47°); QS is opposite the angle R (70°); RS is opposite the angle Q (63°);
2) the rule is: greater angle is opposite the longer side;
3) according to the rule the angle 'S' is the smallest, then the side QR is the shortest.
Answer:
Mariam went to the store 5 times, while Sana went 3 times.
Step-by-step explanation:
Since Mariam and Sana are excited that a new store just opened in town, and they go together the first day it opens, and each time Mariam goes to the store she plans to spend Rs. 30, and each time Sana goes to the store she plans to spend Rs. 50, and a few weeks from now, Mariam and Sana are surprised to find out that they have spent the exact same total amount of money at the store, to determine what is the least possible number of times that Mariam has been to the store the following mathematical reasoning has to be done:
To know how many times Mariam went and how many times Sana went to the store, since she spends Rs. 30 and the other Rs. 50, and they have spent the same after a few weeks, it is through the search for the lower common multiple of both numbers.
Thus, the common multiple less than 30 and 50 is 150 (30 x 5 or 50 x 3). Therefore, Mariam went to the store 5 times, while Sana went 3 times.
Answer:
10/14, 15/21, and 20,28
Step-by-step explanation:
You just need to multiply a number on the numerator and the denominator. Remember, whatever you do to the numerator you have to do on your denominator.
