31.4/3.14=10
10/2=5
5*5*3.14= 78.5 cm square
The length of the rectangle is x and the height is x-2
To find the area of a rectangle you multiply length times width
l(w) = 146
x(x-2) = 146
x^2 - 2x = 146
Here we are given the three sides of the triangle.
So we have Heron's formula to find its area.
Heron's formula is given by :

where A, B and C are sides of triangle and S is semi perimeter which is given by,

plugging values of A, B and C to find S

S=13.5
Now plugging values of A, B , C and S in Heron's formula

A=26.14 mm²
Answer: Area of triangle is 26.14 mm².
Find the perimeter of the polygon with the vertices g(2, 4), h(2,−3), j(−2,−3), g(2, 4), h(2,−3), j(−2,−3), and k(−2, 4)k(−2, 4)
Julli [10]
<span>The distance between g and h is sqrt[(2-2)^2+(4+3)^2]=7
The distance between h and j is sqrt[(2+2)^2+(-3+3)^2]=4
The distance between j and k is sqrt[(-2+2)^2+(-3-4)^2]=7
The distance between k and g is sqrt[(-2-2)^2+(4-4)^2]=4
The perimeter of the polygon is 7+4+7+4=22</span>
No 6.2 could be put as 6.20 and 1.75
6 is bigger than 1