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Nana76 [90]
3 years ago
9

Simplify the expression. t + 2 + 6t =

Mathematics
1 answer:
agasfer [191]3 years ago
7 0
The answer i got is:
5t+2
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12-2(7x-3)=3(1-2x)-5x
vfiekz [6]
12 - 2(7x - 3) = 3(1-2x) - 5x
12 - 14x + 6 = 3 - 6x - 5x
-14x + 6x + 5x = 3 - 12 - 6
-3x = -15
x = -15/-3
x = 5
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3 years ago
A what are two angles that share a common vertex and a common side
Sergio [31]
Im not sure but i think its adjacent
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405 degrees to radians in terms of pi
Katena32 [7]
Convert degrees to radians, multiply by π/180° , since a full circle is 360 ° 360 or 2π radians.
− 405°⋅ π /180° radians

Cancel the common factor of 45 .
-9 ⋅ π/4 radians

Combine −9 and π/4
-9π/4

Move the negative in front of the fraction.
-9π/4 radians
3 0
3 years ago
Rewrite this formula to convert Fahrenheit to Celsius. F= 9/5C + 35
iVinArrow [24]

Answer:

\huge \purple { \boxed{ C = \frac{5}{9} ( F  - 32)}}

Step-by-step explanation:

I the given problem, there should be 32 in place of 35.

F =  \frac{9}{5}  C + 32 \\ F  - 32=  \frac{9}{5}  C \\ 5( F  - 32)=  9  C \\  \frac{5}{9} ( F  - 32)=C \\  \\ \huge \red{ \boxed{ C = \frac{5}{9} ( F  - 32)}}

7 0
3 years ago
Dashawn started to monitor how many calories he consumed during breakfast and lunch. 55% of his calories came from his breakfast
Contact [7]

Answer:

The total calories consumed from both meals = 1595.6 calories

Step-by-step explanation:

Given:

Dashawn had 55% of his calories from his breakfast.

He consumed 718 calories during lunch

To find the total calories he consumed from lunch and breakfast.

Solution:

Dashawn is monitoring his calories for breakfast and lunch only.

So, if he consumes 55% calories during breakfast, then percentage of calories  he consumes during lunch = 100-55=45\%

<em>Let total calories he consumes from both meals be = x</em>

<em>Thus, calories he consumes during lunch can be given as :</em>

⇒ 45\%\ of\ x

⇒ \frac{45}{100} \times x

⇒ 0.45 \times x

⇒ 0.45x

<em>We know that calories taken during lunch = 718.</em>

So, we have,

0.45x=718

Solving for x

Dividing bot sides by 0.45

\frac{0.45x}{0.45}=\frac{718}{0.45}

x=1595.55\approx 1595.6

Thus, the total calories consumed from both meals = 1595.6 calories

4 0
4 years ago
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