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liraira [26]
3 years ago
11

A seamstress uses 12 yards of fabric to make 3 costumes for students in the chorus. How many yards will she need to make costume

s for all 25 students in chorus?
Mathematics
2 answers:
Step2247 [10]3 years ago
7 0

Answer:

100 yards

Step-by-step explanation:

It takes 4 yards of fabric to make a costume for one student.  She needs to make costumes for every student in chorus, so you just multiply this number by 25 and get 100 yards.

AleksAgata [21]3 years ago
6 0

Answer:

100 yards.

Step-by-step explanation:

We have been given that a seamstress uses 12 yards of fabric to make 3 costumes for students in the chorus.

We will use proportions to solve the given problem.

\frac{\text{Yards of fabric}}{\text{Costumes}}=\frac{12}{3}

\frac{\text{Yards of fabric}}{25}=\frac{12}{3}

\frac{\text{Yards of fabric}}{25}*25=\frac{12}{3}*25

\text{Yards of fabric}=4*25

\text{Yards of fabric}=100

Therefore, 100 yards of fabric is needed to make costumes for 25 students.

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Step-by-step explanation:

a || b and a line intersecting them is their transversal.

\therefore m\angle 1=m\angle 5\\(corresponding \:\angle 's) \\\\\therefore 60 - 2x = 70 - 4x\\\\\therefore 4x - 2x = 70 - 60\\\\\therefore 2x = 10\\\\\therefore x =\frac{10}{2} \\\\\huge \orange {\boxed {\therefore x = 5}}

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What is the average size of a toothpick
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Y=1x+2 (you don’t have to write the 1 in front of the x so you can write it as y=x+1)
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3 years ago
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
3 years ago
Question2 of 25If ASTU AABC, which congruences are true by CPCTC? Check all that apply.
Marysya12 [62]

If triangle STU  ≅ triangle ABC, then ∠T ≅ ∠B, ∠S ≅ ∠A, and segment TU ≅ Segment BC are true by CPCTC. Option A, option B, and option D are correct.

Let's understand what is the congruence of the triangle.

If all three corresponding sides are equal and all three corresponding angles are identical in measure, two triangles are said to be congruent. These triangles can be moved, rotated, flipped, and turned to look exactly the same.

CPCTC stands for corresponding parts of congruent triangles are congruent.

Let's check in the triangle STU and triangle ABC;

triangle STU  ≅ triangle ABC

So,

∠S ≅ ∠A

∠T ≅ ∠B

∠U ≅ ∠C

segment ST ≅ Segment AB

segment TU ≅ Segment BC

segment SU ≅ Segment AC

Thus, if triangle STU  ≅ triangle ABC, then ∠T ≅ ∠B, ∠S ≅ ∠A, and segment TU ≅ Segment BC are true by CPCTC. Option A, option B, and option D are correct.

To learn more about the congruence of the triangle visit:

brainly.com/question/19258025

#SPJ9

3 0
11 months ago
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