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liraira [26]
3 years ago
11

A seamstress uses 12 yards of fabric to make 3 costumes for students in the chorus. How many yards will she need to make costume

s for all 25 students in chorus?
Mathematics
2 answers:
Step2247 [10]3 years ago
7 0

Answer:

100 yards

Step-by-step explanation:

It takes 4 yards of fabric to make a costume for one student.  She needs to make costumes for every student in chorus, so you just multiply this number by 25 and get 100 yards.

AleksAgata [21]3 years ago
6 0

Answer:

100 yards.

Step-by-step explanation:

We have been given that a seamstress uses 12 yards of fabric to make 3 costumes for students in the chorus.

We will use proportions to solve the given problem.

\frac{\text{Yards of fabric}}{\text{Costumes}}=\frac{12}{3}

\frac{\text{Yards of fabric}}{25}=\frac{12}{3}

\frac{\text{Yards of fabric}}{25}*25=\frac{12}{3}*25

\text{Yards of fabric}=4*25

\text{Yards of fabric}=100

Therefore, 100 yards of fabric is needed to make costumes for 25 students.

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Function f, shown below, is translated down 3 units and left 4 units to create function g.
pantera1 [17]

Answer: G(x) = 3|x + 2| - 8

<u>Step-by-step explanation:</u>

"a" represents the vertical stretch <em>(or shrink)</em>

"h" represents the x-coordinate of the vertex

  • x-axis goes left and right

"k" represents the y-coordinate of the vertex

  • y-axis goes up and down

F(x) = 3|x - 2| - 5

G(x) = 3(x - 2 + 4| - 5 - 3

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6 0
3 years ago
Read 2 more answers
In a certain neighborhood, there's a sagging power line between two utility poles. The utility poles are 50 feet tall and 120 fe
e-lub [12.9K]
<h3>Answer:  33.75 feet</h3>

In fraction form, this value is equal to 135/4

33.75 ft is equivalent to 33 ft, 9 inches.

===============================================

Explanation:

Refer to the diagram below.

The key point to start with is point H, which is the vertex of the parabola.

Recall that vertex form is

y = a(x-h)^2 + k

What we'll do is plug in the vertex (h,k) = (60,30) which is the location of point H. We'll also plug in (0,45) which is the y intercept, aka the location of point C.

So,

y = a(x-h)^2 + k

y = a(x-60)^2 + 30 .... plug in vertex

45 = a(0-60)^2 + 30 .... plug in y intercept coordinates

45 = a(-60)^2 + 30

45 = a(3600) + 30

45 = 3600a + 30

45-30 = 3600a

3600a = 15

a = 15/3600

a = 1/240

This then means:

y = a(x-h)^2 + k

y = (1/240)(x-60)^2 + 30

This is the equation of our parabola. Plug in x = 30 to determine the height of point K

y = (1/240)(x-60)^2 + 30

y = (1/240)(30-60)^2 + 30

y = (1/240)(-30)^2 + 30

y = (1/240)(900) + 30

y = 15/4 + 30

y = 15/4 + 120/4

y = 135/4

y = 33.75

Therefore, the height of the power line, when it is 30 feet away from one of the poles, is 33.75 feet. This is the y coordinate of point K.

Side note: 33.75 ft = 33 ft + 0.75 ft = 33 ft + 12*0.75 in = 33 ft + 9 inches

8 0
2 years ago
9x-1=1/2(15x-47) I need help
NikAS [45]

Answer:

The answer is x= -15

6 0
2 years ago
a water balloon is tossed into the air with an upward velocity of 25 ft/s its height h(t) in ft after t seconds is given by the
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When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
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0=ax²+bx+c
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so for
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x=\frac{-25+/-\sqrt{25^2-4(-16)(3)}}{2(-16)}
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x=\frac{-25+/-\frac{817}}{-32}
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4 0
3 years ago
2x + x + x + 2y × 3y × y​
Vilka [71]

Answer:

\large\boxed{4x+6y^3}

Step-by-step explanation:

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