Question

Point charges q1=− 5.00 nC and q2=+ 5.00 nC are separated by distance 3.30 mm , forming an electric dipole.

Answer 1

Answer:

(a) The electric dipole moment is equal to 16.5×10^-12 Cm

(b) The electric dipole moment is directed along the dipole axis from the negative charge to the positive charge.

(C) Torque on the dipole is equal to the products of the Electric field vector and the dipole moment

The magnitude is given by

pE×Sin(phi)

Explanation:

The dipole moment is equal to the productof the magnitude of the charge and the distance of separation between the charges.

The detailed solution to the problem is contaimed in the attachment below.

Thank you for reading.