Point charges q1=− 5.00 nC and q2=+ 5.00 nC are separated by distance 3.30 mm , forming an electric dipole.
1 answer:
Answer:
(a) The electric dipole moment is equal to 16.5×10^-12 Cm
(b) The electric dipole moment is directed along the dipole axis from the negative charge to the positive charge.
(C) Torque on the dipole is equal to the products of the Electric field vector and the dipole moment
The magnitude is given by
pE×Sin(phi)
Explanation:
The dipole moment is equal to the productof the magnitude of the charge and the distance of separation between the charges.
The detailed solution to the problem is contaimed in the attachment below.
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The angle above the horizontal of the motion of mass A + B after the collision. as well as others are mathematically given as
- vf/vA= 0.94
- 2vf^2 / 5vA^2 = 0.35
<h3>What is Collison equilibrium?</h3>
According to the collision hypothesis of chemistry, chemical reactions happen when two molecules or atoms collide.
Generally, the equation for Collison equilibrium is mathematically given as
For horizontal motion
mvAx+m2vAx = 2mvfx
For vertical motion
-mvAy+m2vAy = 2mvfy
vfy = 1/2 vAy
(b)
vf/vA= 0.94
(c)
2vf^2 / 5vA^2 = 0.35
In conclusion, The angle above the horizontal of the motion of mass A + B after the collision. as well as others
vf/vA= 0.94
2vf^2 / 5vA^2 = 0.35
Read more about collision theory
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