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3 years ago

Can someone please help me get this right pleaseee I’ll mark brainless .

Physics

2 answers:

Katarina [22]3 years ago

4 0

Answer:i think it is c

Explanation:

Papessa [141]3 years ago

4 0

Answer:

Explanation: i think its c to try it

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The two kinds of motion are horizontal and vertical

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1. What is the temperature in Kelvin and Fahrenheit of silver at 51.4oC?1. What is the temperature in Kelvin and Fahrenheit of s

horsena [70]

Answer:

Temperature in Fahrenheit will be 124.52°F and in kelvin 324.4 K

Explanation:

We have given temperature in of silver in degree Celsius as $51.4^{\circ}C$

We have to convert this temperature in Fahrenheit and kelvin

For Fahrenheit

Temperature in Fahrenheit = $\frac{9}{5}\times 51.4+32=124.52^{\circ}F$

For kelvin

In kelvin = 51.4+273 = 324.4 K

So temperature in Fahrenheit will be 124.52°F and in kelvin 324.4 K

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The gravitational attraction between a 20 kg cannonball and a 0.002 kg

Naya [18.7K]

Answer:

$2.966\times 10^{-11}\ N$

Explanation:

Given:

Mass of the cannonball (M) = 20 kg

Mass of the marble (m) = 0.002 kg

Distance between the cannonball and marble (d) = 0.30 m

Universal gravitational constant (G) = $6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2}$

Now, we know that, the gravitational force (F) acting between two bodies of masses (m) and (M) separated by a distance (d) is given as:

$F=\dfrac{GMm}{d^2}$

Plug in the given values and solve for 'F'. This gives,

$F=\frac{(6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2})\times (20\ kg)\times (0.002\ kg)}{(0.30\ m)^2}\\\\F=\frac{6.674\times 20\times 0.002\times 10^{-11}\ m^3 kg^{-1+2} s^{-2}}{0.09\ m^2}\\\\F=2.966\times 10^{-11}\ kg\cdot m\cdot s^{-2}\\\\F=2.966\times 10^{-11}\ N.........(1\ N = 1\ kg\cdot m\cdot s^{-2})$

The same force is experienced by both cannonball and marble.

Therefore, the gravitational force of the marble is $2.966\times 10^{-11}\ N$

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Empirical because it is what you need to know the source of knowledge gather by observation or experimentation.

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