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3 years ago

Simplify (8(2)/(3))^(4)

Mathematics

1 answer:

Dmitrij [34]3 years ago

5 0

Answer:

16/81

Step-by-step explanation:

according to BODMAS-first settle the bracket

8×2=16

3^4=81

therefore it becomes

16/81.

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100 points !!! Please help

noname [10]

$DERIVATIVE \: \: OF \: \: \\ \: \: \: \: \:PARAMETRIC \: \: FUNCTIONS\\ \\ \\ x = a( \beta - \sin( \beta ) ) \\ y = a(1 - \cos( \beta ) \\ \\ \frac{dy}{d \beta } = a \sin( \beta ) \\ \\ \frac{dx}{d \beta } = a(1 - \cos( \beta ) \\ \\ \frac{dy}{dx} = \frac{a \sin( \beta ) }{a(1 - \cos( \beta ) } = \cot( \frac{ \beta }{2} ) \\ \\ \\ \frac{d^{2}y }{d {x}^{2} } = \frac{d}{dx} ( \ \ \cot ( \frac{ \beta }{2} ) ) = ( - \frac{1}{2} cosec ^{2} \frac{ \beta }{2} ) \times \frac{d \beta }{dx} \\ \\ \\ = (- \frac{1}{2} cosec^{2} \frac{ \beta }{2} ) \times \frac{1}{a(1 - \cos( \beta ) } \\ \\ \\ At \: \beta = \pi \\ \\ = ( - \frac{ 1}{2} {cosec}^{2}\frac{\pi}{2} ) \times \frac{1}{a(1 - \cos(\pi)) } \\ \\ = - \frac{1}{2} . {1}^{2} \times \frac{1}{a(1 - ( - 1))} \\ \\ \\ = - \frac{1}{4a} \: \: \: \: \: \: \: \: \: Ans.$

8 0

2 years ago

The quadratic equation x2 + mx + q = 0, where m and q are real numbers, has the complex root a + bi.?

Sphinxa [80]

Remember the quadratic formula determinant?
If b^2 -4ac < 0, a complex root exists.

So for this problem, m^2 - 4q is the determinant, and if less than 0, is complex.

So a=-m/2 and b=(1/2)SQRT(m^2 - 4q)

3 0

3 years ago

Complete the proof with the statements and reasons below. Write the letter of the statement or reason in the box.

maw [93]

Base on the question that said to write the letter of the statement or the reason in the said numbers in the question, and in my further analysis and research, the following are the answers:
Statements:
#1  C. x=15
#2   G. 3x-12=33
#3  L. 3x=45
#4 O. 3x+0=45
#5 <span>s. 3(x-4)=33
</span>
Reasons:
#1 R. Given
#2 F. Subtraction Property of Equality
#3 I. Division Property of Equality
#4 E. Addition Property of Equality
#5 <span>Distributive Property</span>

8 0

3 years ago

In a scale drawing, a building has a length of 15 cm. The actual length of the building is 37.5 feet. Whats the scale of the dra

Feliz [49]

Answer:

$\frac{15}{37.5}\ \frac{cm}{ft}$

$1.31:100$

Step-by-step explanation:

we know that

The scale of the drawing is equal to divide the length of a building in the scale drawing by the actual length of a building

$\frac{15}{37.5}\ \frac{cm}{ft}$

That means

15 cm in the drawing represent 37.5 ft in the actual

Remember that

$1\ ft=30.48\ cm$

Convert 15 cm to ft

divide by 30.48

$15\ cm=15/30.48\ ft$

substitute

$\frac{15}{37.5}\ \frac{cm}{ft}=\frac{(15/30.48)}{37.5}=\frac{0.0131}{1}$

$1.31:100$

That means

1.31 units in the drawing represent 100 units in the actual

5 0

3 years ago

Will mark as brainliest (must show work)

Sever21 [200]

Answer:

Step-by-step explanation:

With those problems if you are not given a picture is good we draw one.

Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW then

m < XVY = m < YVW

2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms

2x-x = 15-7, combine like terms

x = 8

From the picture and the given we see that

m < XVW = m < XVY + m < YVW

m < XVW = 2x+7 + x+15 , combine like terms

m < XVW = 3x + 22, substitute x for 8

m < XVW = 3*8 + 22

m < XVW = 46

Check our work:

m < XVY = 2x+7 = 2*8 +7 = 16 +7 = 23

m < YVW = x+15 = 8 +15 = 23

m < XVW = m < XVY + m < YVW = 23+23 =46

3 0

2 years ago