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nasty-shy [4]
3 years ago
8

Please please answer this correctly

Mathematics
1 answer:
ryzh [129]3 years ago
3 0

Answer:

it should be 1/2

Step-by-step explanation:

because the sequence is going down by 0.05 each time;

7/10= 0.70

13/20= 0.65

3/5= 0.6

11/20= 0.55

so to continue the pattern,

1/2= 0.5

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Determine the domain of the function.
ziro4ka [17]
f(x)=\sqrt{1-x}\\\\The\ domain:1-x\geq0\ \ \ \ \ |subtract\ 1\ from\ both\ sides\\\\-x\geq-1\ \ \ \ \ |change\ signs\\\\x\leq1

Answer: C. x≤1.
7 0
3 years ago
Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States. In Australia, only 1.5% of
Naddik [55]

Answer:

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

Step-by-step explanation:

For each U.S. resident, there are only two outcomes possible. Either they have blood type AB, or they do not. This means that we can solve this problem using binomial probability distribution concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

50 U.S residents are sampled, so n = 50

4% of the U.S population has blood type AB, so p = 0.04.

What is the probability that exactly 2 of the U.S. residents have blood type AB?

This is P(X = 2). So:

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{50,2}.(0.04)^{2}.(0.96)^{48} = 0.2762

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

5 0
3 years ago
I need help can you guys help me?
9966 [12]

Answer:

G is your answer

Step-by-step explanation:

4 0
3 years ago
Express 110111 base two to base ten​
lidiya [134]

Answer:

zh

Step-by-step explanation:

4 0
3 years ago
A curve has the equation y = x^3 + 3x^2 − 16x + 2. a) Find an equation of the tangent to the curve at the point P (2, −10). Ive
Vesnalui [34]
The equation of the tangent to the curve at the point P(2, -10) is:
y = 8x - 26
f(x)=x^{3}+3x^{2}-16x
f'(x)=3x^{2}+6x-16
f'(2)=12+12-16=8
We need to find the coordinates of point Q where the slope of the tangent to the curve f(x) must also be 8.
f'(x)=3x^{2}+6x-16=8
Now we have a quadratic:
3x^{2}+6x-16-8=0
which simplifies to:
x^{2}+2x-8=0
which factorizes to:(x + 4)(x - 2) = 0
Therefore x = -4, 2.
f(-4) = 48
Therefore the coordinates of Q are (-4, 48).
3 0
3 years ago
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