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Delicious77 [7]
3 years ago
5

Find the first, fourth, and eighth terms of the sequence. A(n) = –5 • 3n–1

Mathematics
2 answers:
jeka943 years ago
6 0

Answer:

<h2>C. -5; -135, -10,935</h2>

Step-by-step explanation:

\text{Substitute}\ n=1,\ n=4\ \text{and}\ n=8\ \text{to}\ A(n)=-5\cdot3^{n-1}:\\\\A(1)=-5\cdot3^{1-1}=-5\cdot3^0=-5\cdot1=-5\\\\A(4)=-5\cdot3^{4-1}=-5\cdot3^3=-5\cdot27=-135\\\\A(8)=-5\cdot3^{8-1}=-5\cdot3^7=-5\cdot2,187=-10,935

Sindrei [870]3 years ago
3 0

Answer:

c

Step-by-step explanation:

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I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help
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<u>Step-by-step explanation:</u>

a)

A=P\bigg(1+\dfrac{r}{n}\bigg)^{nt}

  • A: accumulated amount (balance)
  • P: principal amount (original/initial investment)
  • r: interest rate (convert to a decimal)
  • n: number of times compounded per year
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Given: A = 1800, P = 900, r = 8% = 0.08, n = 3, t = unknown

1800=900\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\2=\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=ln \bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=3t\ ln\bigg(1+\dfrac{0.08}{3}\bigg)\\\\\\\dfrac{ln\ 2}{3\ ln\bigg(1+\dfrac{0.08}{3}\bigg)}=t\\\\\\\large\boxed{8.779=t}

b)  

A=Pe^{rt}

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4 0
3 years ago
What are the solutions of 3x2 + 14x + 16 = 0?
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Good evening ,

Answer:

x = StartFraction negative 8 Over 3 EndFraction, –2

Step-by-step explanation:

3x² + 14x + 16 = 0

3x² + 6x + 8x + 16 = 0

(3x² + 6x) + (8x + 16) = 0

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Step-by-step explanation:

3 + 3 = 6

(1/5)3 = 0.6

(1/5)6 = 1.2

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